Latest TCS Aptitude Question SOLUTION: Form the 8 digit number using 1,2,3,4,5 repetition is allowed and it must be divisible by 4?

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(#M40033853) TCS Numerical Ability question Keep an EYE

Form the 8 digit number using 1,2,3,4,5 repetition is allowed and it must be divisible by 4?

Asked In TCS shanthi (10 years ago)

Unsolved Read Solution (14)

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MUDIT SHARMA  (10 years ago)

Ans should be 5^7=78125
Reason:
We have to form 8 digit number using 1,2,3,4,5 which should be divisible by 4.
To check divisibility for 4 we need to focus on last 2 digits.
Last 2 digit should be divisible by 4. There can be 5 numbers that we can form-12,24,32,52,44.
So in _ _ _ _ _ _ (_ _) last 2 digit we can use these 5 numbers. And in first six (_ _ _ _ _ _)_ _ we can use any 5 digits & as repetition is allowed. So final answer is (5*5*5*5*5*5)*5 = 5^7 = 78125.
Hope this will help!

Is this solution Helpfull? Yes (86) | No (3)  

nikhil khandelwal  (10 years ago)

ans should be 62500
last two digit will be 12,24,32,44 because the given digits are 1,2,3,4,5
and if the no. is divisible by 4 then last two digit must be divisible by 4.
_ _ _ _ _ _ _ _

because no is repeated so
5c1 * 5c1 * 5c1 * 5c1 * 5c1 * 5c1 * 4c1
=62500

Is this solution Helpfull? Yes (4) | No (3)  

Debojit Pal  (9 years ago)

We have to form 8 digit number using 1,2,3,4,5 which should be divisible by 4.
To check divisibility for 4, last 2 digits must also be divisible by 4.
There can be 5 numbers that we can form-12,24,32,44,52.
So in _ _ _ _ _ _ (_ _) last 2 digit must contain these 5 numbers.
And in first six (_ _ _ _ _ _)_ _ we can use any 5 digits & as repetition is allowed.
So final answer is (5*5*5*5*5*5)*5 = 5^7 = 78125.
Hope this will help!

Is this solution Helpfull? Yes (4) | No (1)  

judy tresa  (10 years ago)

5*5*5*5*5*5*(2*2*2*)
125000.
form means?? there can be many numbers

Is this solution Helpfull? Yes (3) | No (7)  

sai  (9 years ago)

8 digit number using 1,2,3,4,5 divisible by 4
last two digits must be divisible by 4 so last two places can be filled in 5 ways like 12,24,44,52,32
remaining 6 places can be filled using all 5 digits as repetition is allowed so
5*5*5*5*5*5*5 = 5^7

Is this solution Helpfull? Yes (3) | No   

OUJASWAEE DAS  (9 years ago)

last digits of the no to b divisibe by 4 should be 12 24 32 52 44
so rest 6 digits can any of 5 digits
total ways are (5*5*5*5*5*5)*5=78125

Is this solution Helpfull? Yes (3) | No   

sushil kumar  (9 years ago)

last two digit should be-12,24,32,52,44
and repetition is allowed so previous 6 places can be filled by
5^6
so total nos =5^6*5

Is this solution Helpfull? Yes (2) | No (1)  

Aarzoo Trehan  (9 years ago)

It should be 2 * (5^6) = 31250
as only two cases are possible i.e. either 12 or 24 at the end.

Is this solution Helpfull? Yes (1) | No   

prabhjot  (9 years ago)

ans is 5^7=78125.
because the last two digits should be 12,24,32,44,52. acc to divisibility rule .
so by fixing these digits at last , no. of ways for each are=5^6.
but total cases are 5,so total no of ways are 5^7.

Is this solution Helpfull? Yes (1) | No   

ranjan kumar  (9 years ago)

a no. divisible by 4 has last 2 digits divisible by 4 so,it may be 12 16 24 28 32 36 44 48 52 56 i.e 10 , so last 2 digits can be filled by 10 ways and rest of 6 by 5 ways each as repetition is allowed..so soln will be
5*5*5*5*5*5*5*10

Is this solution Helpfull? Yes | No (2)  

ranjan kumar  (9 years ago)

sry my explanation was abit wrong it would be 5*5*5*5*5*5*5*5 because the nos will be 12 24 32 44 52.

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Goldi kumari  (9 years ago)

51*5!*5!*5!*5!*5!+3=123

Is this solution Helpfull? Yes | No (2)  

sruthi  (9 years ago)

5*5*5*5*5*5*2*1==15625*2=31250
since it should be divisible by 4, so last two digit shud be divisible by 4
in that way it has only 2 ways of 24 or 42

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sushil kumar  (9 years ago)

last two digit should be-12,24,32,52,44
and repetition is allowed so previous 6 places can be filled by
6^8
so total nos =6^8*5

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