Latest TCS Aptitude Question SOLUTION: Find the value of “n” where 348 + 31996 + 33943 + 33n. Option 1) 1963 2) 1964 3) 1960 4) 1991

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(#M40033865) TCS Numerical Ability question TCS Keep an EYE

Find the value of “n” where 348 + 31996 + 33943 + 33n.
Option
1) 1963
2) 1964
3) 1960
4) 1991

Asked In TCS sree (10 years ago)

Solved RAKESH Read Solution (3)

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Read Solution (3) :

RAKESH  (10 years ago)

3^48 + 3^1996 + 3^3943+3^3n
(3^16 )^3 + 3^1996 + 3^3943 + (3^n)^3
its expansion of (a+b)^3=a^3+3a^2b+3ab^2+b^3

=> 3*(3^16)^2*3^n=3^1996
=> 3^(33+n)=3^1996
=> n = 1963

Is this solution Helpfull? Yes (36) | No (5)  

VIVEK KUMAR  (7 years ago)

Right question is 3^48+3^1996+3^3943+3^3n
so check the difference b/w to power 1996-48=1948.
again check then we will get 3943-1996=1947.
so here we can see that the difference b/w 1st two power and 2nd two power decreased by 1.
so we can write for 3rd power i.e.
3n-3943=1946
n=1963 answer

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nitika agarwal  (8 years ago)

plz explain

Is this solution Helpfull? Yes | No (1)  

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