Latest TCS Aptitude Question SOLUTION: What is the distance between the z intercept from x intercept in the equation ax+by+cz+d=0?

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Trigonometry

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40033889) TCS Numerical Ability question probability Keep an EYE

What is the distance between the z intercept from x intercept in the equation ax+by+cz+d=0?

Asked In TCS swathi (10 years ago)

Solved RAKESH Read Solution (3)

Is this Puzzle helpful?   (6)   (3) Submit Your Solution Trigonometry

Read Solution (3) :

RAKESH  (10 years ago)

put y=z=0 in eqn to get x-coordinate=((-d/a),0,0)
put x=y=0 in eqn to get z-cordinate =(0,0,(-d/c))

distance between the z intercept from x intercept =

√((-d/a)^2 + (-d/c)^2) = |d|/√(1/a^2 + 1/c^2) = |d/ac|*√(a^2 + c^2)

Is this solution Helpfull? Yes (37) | No (1)  

Soham Dalwadi  (10 years ago)

The plane crosses the x axis when y = z = 0; similarly x = y = 0 when it crosses the z-axis. We have to make some assumptions about the coefficients a and c---namely that they are not zero so that the plane does actually cross these axes. (Well, there is the other degenerate case in which the plane is the xz-plane y = 0.)
If a and c are nonzero, the intersection of the plane with the x-axis occurs at the point (-d/a,0,0) and that with the z-axis occurs at (0,0,-d/c). The distance between these points is
√((-d/a)^2 + (-d/c)^2) = |d|/√(a^2 + c^2)

Is this solution Helpfull? Yes (2) | No (3)  

Prerna bisen  (5 years ago)

ax + by + cz + d = 0
At the z-intercept, 'x' and 'y' are both zero.
cz + d = 0 --> z = -d/c --> The z-intercept is the point (0, 0, -d/c).

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.