Latest Tech Mahindra Aptitude Question SOLUTION: The arithmatic mean of 2 no is 34 and geomatric mean of two no is 16 then nos will be

• Placement Papers
• /
• Tech Mahindra
• /
• Numerical Ability
• /
• Arithmetic

Tech Mahindra Question Papers: Tech Mahindra Interview Experience(11) TECH MAHINDRA Company Profile

(#M40034004) TECH MAHINDRA Numerical Ability question ap gp Keep an EYE

The arithmatic mean of 2 no is 34 and geomatric mean of two no is 16 then nos will be

Asked In Tech Mahindra (10 years ago)

Solved Avishek Pattanaik Read Solution (11)

Is this Puzzle helpful?   (10)   (5) Submit Your Solution Arithmetic

Read Solution (11) :

Avishek Pattanaik  (10 years ago)

Let the 2 nos. be 'a' and 'b'
Arithmetic mean=(a+b)/2=34 i.e. a+b=68 -----------eqn.1
Geometric mean=(ab)^(1/2)=16 i.e. ab=256
a-b=[(a+b)^2}-4ab]^(1/2)
or, a-b= [(68^2)-(4*256)]^(1/2)=60-------------------eqn.2
Solving eqn.1 &2 we get--
a=64 & b=4
Answer: two nos are 64 & 4

Is this solution Helpfull? Yes (42) | No (1)  

Manasa Nikitha  (10 years ago)

A.M of a and b=>(a+b)/2=34=> a+b=68---(1)
G.M of a and b=>sqrt(a,b)=16=> ab=256
(a-b)^2=(a+b)^2-4ab= (68)^2-(4*256)=>4624-1024=> 3600
(a-b)^2=3600=> a-b=60------(2)
Solving (1) and (2), we get
b=4, a=64

Is this solution Helpfull? Yes (9) | No   

saurav  (10 years ago)

use the options, it will be quicker :P

Is this solution Helpfull? Yes (7) | No   

Ayush Rastogi  (10 years ago)

let nos are a,b
so A.M = (a+b)/2= 34
-----> a+b=68
G.M. sqrrot of ab=16
-----> ab=16*16
soving them a=64, b=4

Is this solution Helpfull? Yes (4) | No (1)  

PARVY GOVIL  (10 years ago)

a+b /2 =34
(ab)^1/2 =16
taking different case of a and b we gt a=4 b=64

Is this solution Helpfull? Yes (1) | No   

sachin kumar  (9 years ago)

i think it can be 2 solutions
a=4 and b=64
a=64 and b=4

if i take 1 case
a+b/2 that is 4+64/2=34
sqrt(4*64)=16

if i take 2 case
a+b/2 ie 64+4/2=34
sqrt(64*4)=16

Is this solution Helpfull? Yes (1) | No (1)  

Amitava  (10 years ago)

From experience the equation will be
a^2-(34x2)a+16^2=0
a^-68a+256=0
Solving..
a = 4 or 64
That's the two numbers.

Is this solution Helpfull? Yes | No   

abhishek pal  (10 years ago)

(X+Y)/2 = 34
SQRT(XY)= 16
(X-Y)^2= (X+Y)^2 - 4XY
ANS = 4 AND 64

Is this solution Helpfull? Yes | No   

Shravya sure  (10 years ago)

arithmatic mean (a+b)/2=34
geometric mean sqrt(ab)=16
so
a+b=68
ab=16*16 that is 16*4*4 = 64*4( its sum is 68)
so the numbers are 64 and 4

Is this solution Helpfull? Yes | No   

arpana singh  (9 years ago)

x+y/2=34;xy^1/2=16
x,y=4,64 or 64,4

Is this solution Helpfull? Yes | No   

mani  (9 years ago)

a+b=68 -->equ 1
ab=256 -->equ 2
b=256/a
sub b in 1
a+256/a=68
a^2 + 256=68a
a^2-68a+256=0
a=4 or 64
ans : a= 4, b=64 or a=64 ,b=4

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.