Latest CTS Aptitude Question SOLUTION: Diamonds value is proportional to its weight. when diamonds broke into pieces in ratio 1:2:3:4:5 total loss in value is 85000. what is the value of the diamond twice the weight of

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Diamonds value is proportional to its weight. when diamonds broke into pieces in ratio 1:2:3:4:5 total loss in value is 85000. what is the value of the diamond twice the weight of original diamond.

Asked In CTS Deepika Maurya (10 years ago)

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Snehasis  (10 years ago)

There will be no loss.

2 (x+2x+3x+4x+5x)=85000 =>x=8500/3
Now it said that value of the diamond is twice the Weight of original diamond therefore,
Value = 2 (x)+2 (2x)+2 (3x)+2 (4x)+2 (5x) = 30x
Then, 30*(8500/3) = 85000.
Therefore their is no loss.

But if you take value of diamond is square of its weight then we will have loss of 74000.

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sowmya kollipara  (10 years ago)

450,000

let weight of the original diamond be 15k ( This number is the sum of the numbers in the ratio given ) ,so, it's value would be 225k^2. Now, the broken diamond's value adds upto 55k^2. So, loss of value is 170k^2 which is 85,000. This gives k^2 = 500.

We need (30k)^2 = 900k^2 = 900* 500 = 450,000

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Vivek  (10 years ago)

Dear, question is wrong. Here, weight= k*(value)^2.

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Vivek  (10 years ago)

Sorry, value= (weight)^2

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shikha verma  (10 years ago)

1,70,000=85000*2

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sathish nageshwaran  (9 years ago)

450,000

let weight of the original diamond be 15k ( This number is the sum of the numbers in the ratio given ) ,so, it's value would be 225k^2. Now, the broken diamond's value adds upto 55k^2. So, loss of value is 170k^2 which is 85,000. This gives k^2 = 500.

We need (30k)^2 = 900k^2 = 900* 500 = 450,000

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