Latest Elitmus Aptitude Question SOLUTION: what is the reminder when a 4 digit no p^2+17;where p is a prime no of form 6x+-1,

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(#M40034196) ELITMUS Numerical Ability question number system Keep an EYE

what is the reminder when a 4 digit no p^2+17;where p is a prime no of form 6x+-1,

Asked In Elitmus shuvaranjan dash (10 years ago)

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RAKESH  (10 years ago)

considering +ve sign
p^2+17 = (6x+1)^2 + 17 = 36x^2+1+12x +17 = 36x^2 + 12x + 18

(p^2+17)/12 => (36x^2 + 12x + 18)/12 => rem = 6

considering -ve sign
p^2+17 = (6x-1)^2 + 17 = 36x^2+1-12x +17 = 36x^2 - 12x + 18

(p^2+17)/12 => (36x^2 - 12x + 18)/12 => rem = 6

for both cases rem = 6

a) only 6

Is this solution Helpfull? Yes (46) | No   

Satanik Hudati  (10 years ago)

Question was like this:

P is a 4 digit prime number;when P^2 + 17 is divided by 12 what is the remainder?
[Hint:- Prime number is denoted by 6x +- 1]

Options:
a) only 6
b) only 4
c) only 4&6
d) cant be determined

Is this solution Helpfull? Yes (22) | No   

PARVY GOVIL  (10 years ago)

atleast give complete questions

Is this solution Helpfull? Yes (4) | No   

AVIJIT  (10 years ago)

question is wrng.p is four digit prime number ,divided by 12.then what will be the remainder? ans will be 6

Is this solution Helpfull? Yes (1) | No (1)  

satish  (8 years ago)

IF u will take +ve sign then (6x+1)^2+17/12
lets take x=2
you will get rem=6
same for -ve sign if you will do the same process but remember square value should be a prime no. you will get reminder 6.
so optin.(a

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manigandan  (10 years ago)

@rakesh pls expln how the rem 6 came...how did u simply
p^2+17=(6x-1)^2+17=36x^2+1-12x+17=36x^2-12x+18

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shivendra pratap singh  (10 years ago)

mr. rakesh please explain with example

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