Latest Maths Olympiad Aptitude Question SOLUTION: The number of common terms in the two sequences 17,21,25,…,417 and 16,21,26,…,466 is a) 78 b) 19 c) 20 d) 77

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The number of common terms in the two sequences 17,21,25,…,417 and 16,21,26,…,466 is
a) 78
b) 19
c) 20
d) 77

Asked In Maths Olympiad Amar Singh (10 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

shikha singh  (10 years ago)

first common term is 21, now the next common term will have a common difference that is the LCM of the common differences of both aps.

Here it is 4*5 = 20

Hence the series of common terms is 21,41,61, and so on

now for the last term it has to be 401.

Hence no of common terms is 401 = 21 + (n-1)20

380/20 = n-1
n=20

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ABHISEK MONDAL  (10 years ago)

1st sequencely 25,29,33,37,41,45,49,53,57,61,65,69,73,77.(each distance is 3).
2nd sequencely 26,31,36,41,46,51,56,61,66,71,76.option is 77

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anu joshi  (10 years ago)

plz explain how 77 is the answer

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Deepak Reegan A  (9 years ago)

21,41,61,81,101,121,141,161,181,201,221,241,261,281,301,321,341,361,381,401,421,441,461, the common numbers for the above series are 20 like common terms , the total numbers in common are 23 oly.
explanation 17 start series numbers are difference of 4 and 16 start series difference of 5. in this two series the above numbers were common

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