Latest Gmate Aptitude Question SOLUTION: Q. If u,v,w,x,y and z are non negative integer ,each less than 11,then how many distinct combination(u,v,x,y,z) satisfy v(11^4)+w(11^3)+x(11^2)+y(11)+z(1)=151001

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Q. If u,v,w,x,y and z are non negative integer ,each less than 11,then how many distinct combination(u,v,x,y,z) satisfy v(11^4)+w(11^3)+x(11^2)+y(11)+z(1)=151001

Asked In Gmate char (13 years ago)

Solved Dr.Dipin Singh Read Solution (3)

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Read Solution (3) :

Dr.Dipin Singh  (13 years ago)

Only 1 distinct combination is possible.
It can be solved by finding corresponding number in base 11.

So here V= 10, W=3,X=4,Y=10,Z=4

If 10 is represeted as V, then no in base 11 is

V34V4

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RUPESH KUMAR  (10 years ago)

Correct answer is : B

Explanation

11(11^3v+11^w+11x+y) + z = 11*13727 + 4 [hence; z = 4] because I=QN+R : (11*13727+4)

repeating the above procedure;

11(11^2v + 11w +x) + y =11*1247 + 10 [y = 10]
11(11v + w ) + x = 11*113 + 4 [x = 4]
11v + w = 11*10 + 3 [v=10 , w=3]

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jitendra  (9 years ago)

z=151001%11=4

value=151001-4=150997

y(11)=150997%121=110

y=110/11=10

value=150997-11*10=150887

x(11^2)=150887%1331=484

x=484/121=4

value=150887-484=150403

w(11^3)=150403%(11^4)=3993

w=3993/1331=3

value=150403-3993=146410

v(11^4)=146410

v=146410/14641=10

one combination z=4,y=10,x=4,w=3,v=10

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