Latest Campus Aptitude Question SOLUTION: Given perimeter of isolated triangle is 6+3root2.find area of triangle?

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(#M40034497) CAMPUS Numerical Ability question Keep an EYE

Given perimeter of isolated triangle is 6+3root2.find area of triangle?

Asked In Campus moumitabhakat (10 years ago)

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hanamant k  (10 years ago)

area of trangle
when sides are given is A=sqrtof(s(s-a)(s-b)(s-c))----(1)
where perimeter s=a+b+c
in our case a,b,c=b ;bcoz isolated trangle
6+3root2=a+2b
a=(6+3root2)-2b

substitute in equ--(1)
and get solution

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karthika kumar  (10 years ago)

area of isoceles triangle=1/4(b*sqt 0f 4a^2-b^2).---(1)
since isoceles a=c,P=2a+b (since Perimeter= a+b+c)
Also b=aroot2 (sice b^2=a^2+a^2)
Therefore P=2a+aroot2
given P=6+3root2 ,6+3root2=2a+aroot2 => a=3
therefore b= 3root2
subsititute a & b in (1), we get Area=9/2

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