Latest Syntel Aptitude Question SOLUTION: In a school there are 1000 students in the year 1999. The number of students increased by 20% in the year 2000. And it is increased by 15% in the year 2001. But it is decreased by

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In a school there are 1000 students in the year 1999. The number of students increased by 20% in the year 2000. And it is increased by 15% in the year 2001. But it is decreased by 18% in 2002. Then what is the strength in 2002.

Asked In Syntel srilatha (13 years ago)

Solved Dr.Dipin Singh Read Solution (8)

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Read Solution (8) :

madhuvu vaddi  (13 years ago)

In 1999 students=1000
In 2000 students=(1000*120)/100=1200
In 2001 students=(1200*115)100=1380
In 2002 students=(1380*82)100=1131.6=1132 (decreased by 18%)

Is this solution Helpfull? Yes (32) | No (2)  

Dr.Dipin Singh  (13 years ago)

strength in 2002 = 1000*1.2*1.15*0.82= 1131.6

so 1132

Is this solution Helpfull? Yes (22) | No   

subhojyoti bose  (13 years ago)

its easy...increasing 1000 by 20% gives 1200
increasing 1200 by 15% gives 1380
then decreasing 1380 by 18% gives 1132

Is this solution Helpfull? Yes (6) | No   

madhuvu vaddi  (13 years ago)

In 1999 students=1000
In 2000 students=(1000*120)/100=1200
In 2001 students=(1200*115)100=1380
In 2002 students=(1380*82)100=1131.6=1132 (decreased by 18%)

Is this solution Helpfull? Yes (5) | No (1)  

madhuvu vaddi  (13 years ago)

In 1999 students=1000
In 2000 students=(1000*120)/100=1200
In 2001 students=(1200*115)100=1380
In 2002 students=(1380*82)100=1131.6=1132 (decreased by 18%)

Is this solution Helpfull? Yes (3) | No (1)  

Rakshit Jain  (13 years ago)

successive increase of 20% and 15% is given by:
20+15+(20*15)/100,i.e 38%
now,38% increase and 18% decrease corresponds to net increase/decrease is given by:
38+(-18)+{38*(-18)/100} i.e, 13.16%(positive means increase).
therefore,net strength in 2002 is given by increase of 13.16% to strength in 1999 i.e,1000 which is given by:
113.16% of 1000 which is equal to 1131.6!!!!!

Is this solution Helpfull? Yes (1) | No   

Prateek Jajoo  (13 years ago)

take the first two increasing percent
apply formula a+b+((ab)/100) (a=20 and b=15)
therefore placing in the value of increase percent is 38%
therefore 38% of 1000 is 38. Therefore population after 2001 is 1380
Now population decrease by 18%, therefore 18% of 1380 is 248.4
so final population is (1380-248.4)=1131.6 or 1132

Is this solution Helpfull? Yes (1) | No   

Nivas  (10 years ago)

In 1999 students=1000
In 2000 students=(1000*120)/100=1200
In 2001 students=(1200*115)/100=1380
In 2002 students=(1380*82)/100=1131.6=1132 (decreased by 18%)

Is this solution Helpfull? Yes | No   

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