Latest TCS Aptitude Question SOLUTION: There are 3 boys and 4 girls. We have to arrange any 1 boy at the centre and any 2 girls at corners. In how many methods these persons can be arranged. OPTIONS: 1) 432 2) 488 3) 51

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There are 3 boys and 4 girls. We have to arrange any 1 boy at the centre and any 2 girls at corners. In how many methods these persons can be arranged.
OPTIONS:
1) 432
2) 488
3) 512
4) 580
5) 624
6) 725
7) 864
8) 1024
9) 1200
10) none of these

Asked In TCS jeetendra kumar (12 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

Dr.Dipin Singh  (12 years ago)

solved on daily puzzle.
4 persons can be placed in 4 unconditional places in 4*3*2= 24 ways
4 girls can be placed in 6 ways at two corner and by replacing corners among two girls, there are 12 ways.
3 boys can be placed in centre in 3 ways.

so total methods = 24*12*3 = 864

Is this solution Helpfull? Yes (14) | No (1)  

saket  (12 years ago)

1 boy in center 3C1 = 3
2 girls at corner 4C2=12
but now 4 (2 girl + 2 boys) is remaining to arrange around to centre so 4! = 24
"and" is using here so we will multiply it . if in this question "or" would there insted of "and" then we will use addition..
3*12*24= 864

Is this solution Helpfull? Yes (8) | No (4)  

Maheshkumar Eaga  (12 years ago)

arrangement of two girls at corner is=4p2=4*3=12
arrangement of one boy at centre is =3p1=3
arrangement of remaining two girls and two boys =4p4=4*3*2=24
TOTAL ARRANGEMENT IS=12*3*24=864

Is this solution Helpfull? Yes (6) | No (1)  

sudeep kumar  (12 years ago)

4c2 * 2! = 12 - 2girls at corner
3c1 = 3 - 1boy at center
4! = 24 - remaining 4
hence, 12 * 3 * 24 = 864

Is this solution Helpfull? Yes (5) | No (2)  

koteswarareddy  (12 years ago)

methods for arranging 1 boy at centre = 3
methods of arranging 2 girls at corner = 4*3 = 12
methods of arranging remaining 4 persons = 4*3*2*1 = 24
so total methods = 3*12*24 = 864

Is this solution Helpfull? Yes (2) | No (3)  

Jai  (12 years ago)

One boy can be picked up and arranged in 3c1 ways.
two girls for the extremes can be picked up and arranged in 4c2 * 2! ways
others can be arranged in 4! ways.

therefore totral number of ways = 3C1 * 4C2 * 2! * 4! = 864
Therefore option 7) 864 is the answer

Is this solution Helpfull? Yes | No (1)  

Ajay khalane  (12 years ago)

3 boys and 4 girls,1 boy @ center & 2 girls @ corner
lets take yke 1 for boy and 2 for girls
then sequence will be 2 1 2 1 2 1 2
take sum of 1st three and last three digit
answer will be 515.
answer out of this ten option is
10) none of these

Is this solution Helpfull? Yes | No (1)  

nakul porwal  (12 years ago)

total 7 position
middle one for boy only=3 ways
ends fo girls= 4c2 *2!
remainig 4 position n 4 people = 4!
total = 3*4c2*2!*4!=864

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Harshita  (12 years ago)

432
it will be 4c2 * 3c1 * 4! =432

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nikhil gupta  (12 years ago)

7

the boy to be seated at the centre can be chosen in 3c1 ways.
two girls to be seated at the corners can be selected in 4p2 ways,, as we have to arrange them also, thereby using permutation.
now we have 2 vacant seats each on either side of the central boy,, so the remaining two girls and 2 boys can arrage themselves in 4! ways among these seats.
so total no of ways= 4p2 * 3c1 * 4! = 864

c -> combinations
p -> permutations

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