Latest IBM Aptitude Question SOLUTION: Last month I sent off for one of those kits which you can use to make your own Christmas Crackers. The kit contained: Three colours of hat: Red, Yellow and Blue Four types of nove

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Last month I sent off for one of those kits which you can use to make your own Christmas Crackers. The kit contained:

Three colours of hat: Red, Yellow and Blue
Four types of novelty: toy car, spinning top, magnifying glass and miniature hair brush
Four different types of joke slip

All the other parts were the same type. The kit contained enough bits for 50 crackers. Can I make each cracker different from all the others?

Asked In IBM Subrata Patra (10 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

srinivasa kalyan  (10 years ago)

yes 3*4*4*remaining give different solutions

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rachna malviya  (9 years ago)

3 x 4 x 4 = 48. Sadly at least two crackers must be exact duplicates of ones already made.
BUT if you could handle the sad look on people's faces, you could consider a missing item as a possible combination. This gives 4 x 5 x 5 = 100 different crackers. 40 crackers would be missing one item, 11 will be missing two, and one cracker with nothing in at all! [COPIED]

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divya tikki  (9 years ago)

is the answer YES or NO..???

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rajesh kumar ranjan  (9 years ago)

ans is 5 because there are 5 rows with atleast 3 chairs

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PROSENJIT DEY  (9 years ago)

no.......
3 x 4 x 4 = 48. Sadly at least two crackers must be exact duplicates of ones already made.
BUT if you could handle the sad look on people's faces, you could consider a missing item as a possible combination. This gives 4 x 5 x 5 = 100 different crackers. 40 crackers would be missing one item, 11 will be missing two, and one cracker with nothing in at all! [COPIED]
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