Latest CAT Aptitude Question SOLUTION: A vessel has a milk solution in which milk and water are in the ratio 4:1. by addition of water to it, milk solution with milk and water in the ratio 4:3 was formed. on replacing 1

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(#M40036521) CAT Numerical Ability question ratio and mixture Keep an EYE

A vessel has a milk solution in which milk and water are in the ratio 4:1. by addition of water to it, milk solution with milk and water in the ratio 4:3 was formed. on replacing 14 L of this solution with pure milk the ratio of milk and water changed to 5:3. what is the volume of the water added?

Asked In CAT shrishti jain (10 years ago)

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pratima kumari  (9 years ago)

32L
M:L= 4:1 => 4x of milk and 1x of water
after adding water M:W =4:3 =>4x of milk and 3x of water(means 2x extra water is added)
now , 14 L IS REPLACED WITH PURE MILK
that means (4x/7x)*14 = 8L of pure milk is removed and (3x/7x)*14 = 6L of water is rmoved from (4x +3x)L of solution
now adding 14L pure milk
(4x-8+14)/(3x-6)=5/3
on solving x =16
therfore 2x = 32 L OF WATER is added

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Dr.Dipin Singh  (10 years ago)

32 litres of water was added.

M....W
64..16.. initially .... ratio = 4:1
64..48... After adding 32 litre water... ratio = 4:3
56..42... removing 14 litre mixture
70..42.... adding 14 litre pure milk .... ratio = 5:3

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gautham  (10 years ago)

after addition of water the ratio is 4:3. so in 14 litres of sol. there is 8 l of milk and 6 lt of water. so when 14 lits of milk is added, actually only 6 lts of milk is added and the water composition is reduced by 6 l.
4x+6/3x-6 = 5/3
x comes to 12 . so water added is 24.

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Anurag Yadav  (9 years ago)

Ans :36 ltr
Let 5x be solution, milk(4x) water(x)
Now y ltr wtr b added then 4x/(x+y)=4/3 on silving we get y=2x
Total solution nw is 5x+2x=7x fom dis 14 ltr taken out which means 8 ltr of milk and 6 ltr of wtr
Hence m:w=(4x-8):(3x-6) nw 14 ltr milk added
New ratio m:w=(4x-8+14):(3x-6)=5:3
On solving x=18
Watr added =2x=36

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