Latest Elitmus Aptitude Question SOLUTION: How many three digit numbers are there in which product of their digit is 36. Ex: 236, in this product of digit is 36

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How many three digit numbers are there in which product of their digit is 36. Ex: 236, in this product of digit is 36

Asked In Elitmus yatinkarel (10 years ago)

Solved RAKESH Read Solution (12)

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Read Solution (12) :

RAKESH  (10 years ago)

if (x,y,z) are digits then x*y*z=36 where x,y,z less than 10

(1,9,4)=> 6 no.s 149,194,419,491,914,941
(1,6,6)=> 3 no.s 166,661,616
(2,9,2)=> 3
(2,6,3)=> 6
(3,4,3)=> 3

total no. = 6+3+3+6+3= 21

Is this solution Helpfull? Yes (165) | No (6)  

raushan kumar  (10 years ago)

21 is right...

Is this solution Helpfull? Yes (9) | No (4)  

Radhakanta Ghosh  (10 years ago)

Sorry friends for last answer.....
That should be:===6+3+3+3+6= 21 numbers

Is this solution Helpfull? Yes (5) | No (1)  

PINAKI MAJUMDAR  (10 years ago)

L.C.F. of 36 is--> 2,2,3,3
so by this we have to make 3 digit no whose product is 36.
so the numbers are as follows
922,292,229
433,343,334
236,263,623,632,362,326

so the total no is= 3+3+6=12

Is this solution Helpfull? Yes (2) | No (16)  

roy  (10 years ago)

1, 2, 3, 4, 6, 9: pick any 3 numbers whose multiple is 36 . there are 21 such numbers

Is this solution Helpfull? Yes (2) | No (1)  

pankaj bajaj  (9 years ago)

24-total
2=236,263,229,292
3=334,343,326,362
4=409,490,419,491,433
6=606,660,623,632,616,661
9=904,940,941,914,922

Is this solution Helpfull? Yes (2) | No (11)  

Anoop  (9 years ago)

36 have prime no multiplication (2,2,3,3)
using these we can form no's and their arrangements
433-3
623-6
922-3
149-6
166-3
so total is 21

Is this solution Helpfull? Yes (1) | No   

ankita soni  (9 years ago)

229,292,922
362,326,263,236,632,623
334,343,433
661,616,166
194,149,491,419,914,941
answer is 21 numbers

Is this solution Helpfull? Yes (1) | No (1)  

Sahil Choudhary  (9 years ago)

21 is correct

Is this solution Helpfull? Yes (1) | No   

Anurag Gupta  (8 years ago)

if (x,y,z) are digits then x*y*z=36 where x,y,z less than 10

(1,9,4)=> 6 no.s 149,194,419,491,914,941
(1,6,6)=> 3 no.s 166,661,616
(2,9,2)=> 3
(2,6,3)=> 6
(3,4,3)=> 3
&
(6,0,6)=>1

ans=6+3+3+6+3+1=22

Is this solution Helpfull? Yes (1) | No (1)  

Chandrashekhar   (10 years ago)

2 3 6 we can arrange them in 6 ways.
2 2 9 we can arrange them in 3 ways
3 3 4 we can arrange them in 3 ways.
totally 12 ways
ans is 12

Is this solution Helpfull? Yes | No (12)  

Radhakanta Ghosh  (10 years ago)

We can make those three digit number of 36 as digit product, By using:-1,3,2,3,2 arrangement.
236:= 236,263,326,362,632,623 =6 numbers
433:= 433,343,334 =3 numbers
922:= 922,292,229 =3 numbers
661:= 661,616,166 =3 numbers
941:= 941,914,419,491,149,194 =6 numbers


The total required numbers =6+3+3+3+6 = 18 (Answer)

Is this solution Helpfull? Yes | No (19)  

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