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Mu Sigma Question Papers: Mu Sigma Interview Experience(1)

(#M40037948) MU SIGMA Numerical Ability question Equations Keep an EYE

m=2- root 3
Find the value of:
(m^6+m^5+m^4+1)/m^3

Asked In Mu Sigma Aditi Swaroop (10 years ago)

Unsolved Read Solution (3)

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Read Solution (3) :

RAKESH  (10 years ago)

m = (2 - √3)
=> 1/m = (2 + √3)

(m^6+m^5+m^4+1)/m^3
= m^3 + m^2 + m + 1/m^3
= (m + 1/m)^3 - 3(m +1/m) + m(m+1)
= 4^3 - 3*4 + (2-√3)(3-√3)
= 64 - 12 + 9 - 5√3
= (61 - 5√3)

Is this solution Helpfull? Yes (17) | No (3)  

VAISHALI K.J.  (9 years ago)

m=2- √3
((2-√3)^6+(2-√3)^5+(2-√3)^4+1)/(2-√3)^3
((2-√3)^6+5+4)+1)/((2-√3)^3
((2-√3)^15)+1/(2-√3)^3
(((2-√3)^15/(2-√3)^3)+1)/((2-√3)^3)
((2-√3)^5)+((2-√3)^-3)
(2-√3)^5-3
(2-√3)^2
4-4√3+3
7-√3

Is this solution Helpfull? Yes | No (6)  

harish agarwal  (6 years ago)

first of all we have to find the value of root 3 that is 1.732
then subtract it from 2 we will get 0.268
we have to take the given powers of m.Then by adding them we will get 3.412
for this value we have to divide it by 3 times of m.
the final answer we will get is 38.198

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