Latest Elitmus Aptitude Question SOLUTION: 10 Bananas, 7 apples and 9 Oranges to be chosen from their respective baskets, such that at least one fruit is chosen from each basket.

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(#M40038039) ELITMUS Numerical Ability question Fruit selection Keep an EYE

10 Bananas, 7 apples and 9 Oranges to be chosen from their respective baskets, such that at least one fruit is chosen from each basket.

Asked In Elitmus Vivek Jain (9 years ago)

Unsolved Read Solution (13)

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Read Solution (13) :

Rahul Nautiyal  (9 years ago)

for 10 bananas we hv 11 choice( 0,1,2,3,4,5,6,7,8,9,10)
similarly 7 apple in 8 ways. & 9 oranges in 10 ways.
total ways. 11*8*10=880
there is one way where no fruit is choosen.

then 880-1 = 879.

Is this solution Helpfull? Yes (35) | No (24)  

Sonali Ghadai  (9 years ago)

in question it is given that at least one fruit is chosen from each basket,so no ways are there to choose zero no of fruit.
so
10*7*9=630.

Is this solution Helpfull? Yes (34) | No (10)  

bisu  (9 years ago)

ans 1

bananas are identical.. so 10 bananas can be chosen in only 1 way..somiliarly for apples and oranges...so ans sud be 1

Is this solution Helpfull? Yes (10) | No (7)  

PANKAJ SINGH BIRORIA  (9 years ago)

@NAUTIYIL bro u r wrong, coz u hv made yur ans for d case, no. of ways fruits can be taken out, when atlest 1 fruit choosen. (bt qus is when atleast 1 fruit is chosn frm EACH BASKET)..........
So,ans should be 10*7*9=630 (no choice to choose nill in each basket).

Is this solution Helpfull? Yes (5) | No (1)  

GAURAV GUPTA  (9 years ago)

11*8*10-1=880-1=879

Is this solution Helpfull? Yes (4) | No (5)  

T.VIGNESWARA REDDY  (9 years ago)

rahul nauityal is right

Is this solution Helpfull? Yes (3) | No (3)  

tirupathi reddy  (9 years ago)

10!*7!*9!*3!

Is this solution Helpfull? Yes (1) | No (3)  

ramanjulu  (9 years ago)

If ram draws 1 then Sam has 22 choices. If ram draws 2 then Sam has 21 choices and so on..

So, the probality that Sam has drawn a card greater than Ram is

=> 1/23*22/23 + 1/23*21/23 + 1/23*20/23 + .... + 1/23*1/23

=> 1/23*[(22+21+...+10)/23]

=> 1/23*{22/2*[1+22]}/23



=> 252/529 or 84/143

Is this solution Helpfull? Yes (1) | No (1)  

priyanka  (9 years ago)

(11*8*10)-1

Is this solution Helpfull? Yes | No (1)  

T.VIGNESWARA REDDY  (9 years ago)

each frit has two chances i.e either taken or not total number ways for atleast one fruit from each basket is (2^10-1)*(2^7-1)(2^9-1)

Is this solution Helpfull? Yes | No (1)  

Sachin Khetarpal  (9 years ago)

11*8*10=880
=880-7
=873

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Arpit dubey  (8 years ago)

630 will be the answer

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Arpit dubey  (8 years ago)

because in the case of "879" you have considered the case of 0 banana or 0 apple or 0 mango.....
but the question is saying that there is no option of choosing nill from any basket....

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