Latest Elitmus Aptitude Question SOLUTION: if 1001 divides a 6-digit number of the form xxyyzz where x!=y!=z leaves the remainder R...what is max value of the remainder R? A)990 B)891 C)561 D)121

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(#M40038120) ELITMUS Category question quant Keep an EYE

if 1001 divides a 6-digit number of the form xxyyzz where x!=y!=z leaves the remainder R...what is max value of the remainder R?

A)990
B)891
C)561
D)121

Asked In Elitmus jitesh bhojwani (9 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

nishant  (9 years ago)

xxyyzz=110099
1001*109+990=110099
i.e ans is (a)990

Is this solution Helpfull? Yes (7) | No (11)  

SUCHIT KUMAR  (9 years ago)

@nishant
i think u skip one condition i.e.x!=y!=z.

Is this solution Helpfull? Yes (3) | No (1)  

Sayan  (9 years ago)

how is 1!=0!=9 if 110099 is xxyyzz?

Is this solution Helpfull? Yes (3) | No (1)  

RAJIV RANJAN  (9 years ago)

@nishant how u have start to solve this question... pls reply

Is this solution Helpfull? Yes (1) | No   

Naina  (9 years ago)

ans (B)
xxyyzz= 110011 or 110000
for case 110000 we get remainder 891
for case 110011 we get remainder 902

Is this solution Helpfull? Yes (1) | No (2)  

ASHISH MUKHERJEE  (9 years ago)

Ans Will be option B. 891

Is this solution Helpfull? Yes (1) | No   

Vivek  (3 years ago)

case 1 x! = y! = z
1! = 0! =1
output is 1 = 1 = 1 condition true make a number 110011

case 2 x!=y!=z
0!=1!=1
output is 1=1=1 condition is true but make a number 001111 so that's why this is not 6 digit number

110011 / 1001 = reminder is 902

Is this solution Helpfull? Yes (1) | No   

jitesh bhojwani  (9 years ago)

nishant you are ryt totally..

Is this solution Helpfull? Yes | No (6)  

abcxyz  (9 years ago)

what is this condition x!=y!=z.????? I cann't understand it. Explain it clearly @ Nishant hw can u take 1001*109+990 there are various other numbers????/

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Ravinder kumar  (9 years ago)

X!=y!=z means x,y and z are not equal to each other.

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