Latest CAT Aptitude Question SOLUTION: a reduction of 20% in the price of orange enables a man to buy 5 more oranges for Rs 10.the price of an orange before reduction:

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(#M40038279) CAT Category question ss Keep an EYE

a reduction of 20% in the price of orange enables a man to buy 5 more oranges for Rs 10.the price of an orange before reduction:

Asked In CAT MohanRaj (9 years ago)

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Ajith  (9 years ago)

P= PRICE OF 1 QUANTITY
Q=NO. OF QUANTITY
E= EXPENDITURE OR TOTAL PRICE
let us assume that my total expenditure is 10Rs
i.e p * q = 10 ............a
now when the price decreases by 20% quantity increases by 5 for 10Rs which means 0.8p * (q+5)=10
=>0.8pq + 4p = 10
but pq=10 from a
so =>0.8 * 10 +4p=10
=>p=0.5
hence original price of 1 orange is 0.5Rs.

Is this solution Helpfull? Yes (3) | No (2)  

Kapil Shirsath  (9 years ago)

Let initially man buys Y number of oranges.
So the price of 1 orange is Y/10=X...(1)
Now when the price reduces,the man buys Y+5 oranges
So the price of 1 orange becomes (Y+5)/10=0.8X...(2)
Equating (1) and (2) and solving and neglecting - sign we get Y=25
So initially,the price of 1 orange is 2.5

Is this solution Helpfull? Yes (1) | No (1)  

aman yash  (9 years ago)

the solution is 40p.

Is this solution Helpfull? Yes | No (3)  

abhishek pal  (9 years ago)

price of 1 orange after reduction = 10/5 = 2
let the price b4 reduction = x
x - (20/100)*x = 2
x= 2.5

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