Latest Elitmus Aptitude Question SOLUTION: Q-[1/3+1/50]+[1/3+2/50]+[1/3+3/50]+.......+[1/3+70/50] what is sum of above series if[.] denote integer value

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Q-[1/3+1/50]+[1/3+2/50]+[1/3+3/50]+.......+[1/3+70/50]
what is sum of above series if[.] denote integer value

Asked In Elitmus Vishnu Kumar (9 years ago)

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RAKESH  (9 years ago)

from (1/3 +1/50) to (1/3 + 33/50) , each term is less than 1

so, [1/3+1/50]+[1/3+2/50]+[1/3+3/50]+.......+[1/3+33/50] = 0

from [1/3 +34/50] to [1/3 +70/50], each term is greater than 1 & have a value 1.
from 34 to 70, no. of terms = 70-34+1 = 37

ans = 1+1+...37 times = 37

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Ravichandran Ashwin  (9 years ago)

anwer is 21 as [1/3]+[1/3]...[1/3] take out common from each of the terms .71*[1/3]=71*0=0 as[0.33..]=0and next terms will continue as[1/50]to [49/50]=0 and from [50/50] to [70/50] 21 terms with value 1 so 21*1 = 21.

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sunil kumar  (9 years ago)

Upto 33/50 the integer will be 0 and after it the integer value will be 1.. I.e.

From 34 to 70
=> (70-34)*1
=> 36+1(including 34)

=> ans. Is 37

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Ashish Kumar gupta  (9 years ago)

this can be written as [1/3+1/3+1/3.....70terms]+[1/50+2+50....70terms]
=[70/3]+(1/50)[1+2+3+4.....70terms]
=[70/3]+(1/50)[2485]
ans=73.03

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saumya shukla  (9 years ago)

1/3(70)+[ (1/50)+(2/50)..........(70/50)]=2191/30;

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