Latest Campus Aptitude Question SOLUTION: in how many ways can 7 different objects can be divided among 3 person so that either one or two do not get any object

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(#M40038792) CAMPUS Numerical Ability question probability Keep an EYE

in how many ways can 7 different objects can be divided among 3 person so that either one or two do not get any object

Asked In Campus amit palanpure (9 years ago)

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NIVEDA SIVAPRAKASAM  (9 years ago)

Ans. 28
7C2+7C1=28
7C2---> if one did not get any object
7C1---> if two of them did not get any objects.

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Kushagra Tiwari  (9 years ago)

Case 1: Two guys don't get anything. All items go to 1 person. Hence, 3 ways.

Case 2: 1 guy doesn't get anything. Division of 7 items among 2 guys. Lets say they are called A & B.

a) A gets 6. B gets 1. 7 ways.
b) A gets 5. B gets 2. 21 ways.
c) A gets 4. B gets 3. 35 ways.
d) A gets 3. B gets 4. 35 ways.
e) A gets 2. B gets 5. 21 ways.
f) A gets 1. B gets 6. 7 ways.
Total = 126 ways to divide 7 items between A & B.
Total number of ways for case 2 = 126*3 = 378 (Either A, or B, or C don't get anything).

Answer = Case 1 + Case 2 = 3 + 378 = 381

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Kushagra Tiwari  (9 years ago)

Sorry i misRead The Questtion

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deepti gupta  (9 years ago)

7c3-(7c2+7c1)
35-28=7
so answer is 7

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preetijaiswal  (6 years ago)

IF TW OF THEM GET NOTHING=(7C0*7C0*7C7)*3!=6
IF ONE O THEM GET NOTHING =(7C1*7C0*7C6)*3!=294
TOTAL=300

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