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(#M40038896) TCS Numerical Ability question Keep an EYE

sum of fibonacci numbers1,6,7,13,20.... upto 52 terms?

Asked In TCS hima (10 years ago)

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Deepak Kumar Sahu  (10 years ago)

Observing the sequence 1, 6, 7, 13, 20 and so on,
It can be re-written as 1, (1+5), (2+5), (3+10), (5+15), (8+25), and so on.

The sequence thus decomposes into sum of two standard Fibonacci sequences,
1, 1, 2, 3, 5, 8, 13 up to 52 terms and 5*(1, 1, 2, 3, 5, 8, 13 up to 51 terms).

So the sum is given as : Sum of 52 terms of the standard Fibonacci series + 5*Sum of 51 terms of the standard Fibonacci series. Which is equivalent to 6*Sum of 51 terms in the standard Fibonacci series + the 52th term. And since sum of n terms of a fibonacci series is given as F(n+2)-1,

The sum should be 6*{F(53)-1}+F(52) = F(52) + 6*F(53) - 6.

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RAVI VERMA  (10 years ago)

SUM OF N TERMS OF FIBBONICA SERIES WILL BE(n+2-1)FIBONNICA NUMBER
EG:
LET FS BE:
1 6 7
SUM OF IST TWO NUMBERS WILL BE THE THIRD NUMBER ACCORDING TO THE FORMULA
SO HENCE 7

Is this solution Helpfull? Yes (2) | No (26)  

richa sharma   (10 years ago)

What is the corrct Ans??

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KOUSHIK DAS  (10 years ago)

kindly post the right formula..

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