Latest TCS Aptitude Question SOLUTION: Given is series 1,2,3,7,7,22,15,67,…,what number will come immediately before 63?

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Given is series 1,2,3,7,7,22,15,67,…,what number will come immediately before 63?

Asked In TCS hima (9 years ago)

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RAKESH  (9 years ago)

1,2,3,7,7,22,15,67,…
its combination of two alternate series

1,3,7,15,31,63,127 => next=(pre*2+1)
2,7,22,67,202,307 => next no.=(pre*3+1)

series is 1,2,3,7,7,22,15,67,31,202,63,307

so, 202 comes immediately before 63.

Is this solution Helpfull? Yes (96) | No   

seshunaga  (9 years ago)

1,2,3,7,7,22,15,67,.........
let 1,3,7,15,....... the series follows as difference of multiples of 2 i.e
3-1=2
7-3=4
15-7=8
31-15=16
63-31=32
.........
let 2,7,22,67,........ series follows the difference if multiples of 3 with 5,15,45,135,........... i.e
7-2=5
22-7=15
67-33=45
202-67=135
.........
so the further numbers of series are 1,2,3,7,7,22,15,67,31,202,63,......
therefore answer is 202

Is this solution Helpfull? Yes (2) | No   

sivaraman  (9 years ago)

1,2,3,7,7,22,15,67,…
its combination of two alternate series

1,3,7,15,31,63,127 => next=(pre*2+1)
2,7,22,67,202,307 => next no.=(pre*3+1)

series is 1,2,3,7,7,22,15,67,31,202,63,307

so, 202 comes immediately before 63.

Is this solution Helpfull? Yes (1) | No (7)  

Sridhar VG  (9 years ago)

CP? I did not understand your steps.better luck next time.

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Maheswar  (9 years ago)

1,2,3,7,7,22,15,67....
3=1+2^1
7=3+2^2
15=7+2^3=31
so next no wii be=31+2^4=ans

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Aman Priya  (9 years ago)

1 2 3 7 7 22 15 67
combination of two series 1 3 7 15.....&2 7 22 67 ...............
1st series 1*2+1=3
3*2+1=7
7*2+1=15
15*2+1=31
31*2+1=63
2nd series 2 7 22 67
2*3+1=7
7*3+1=22
22*3+1=67
67*3+1=202
ultimate series 1 2 3 7 7 22 15 67 31 202 63
ans=63

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