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(#M40039224) TCS Category question Keep an EYE

The milk and water in two vessels A and B are
in the ratio 4 : 3 and 2: 3 respectively. In what
ratio, the liquids in both the vessels are mixed to
obtain a new mixture in vessel C containing half
milk and half water?
a) 8 : 5 b) 9 :4 c) 5: 7 d) 7 : 5

Asked In TCS shikha panwar (10 years ago)

Unsolved Read Solution (5)

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sai  (10 years ago)

Milk in 1 litre mixture of A = 4/7 litre.
Milk in 1 litre mixture of B = 2/5 litre.
Milk in 1 litre mixture of C = 1/2 litre.
By rule of alligation we have required ratio X:Y

X : Y
4/7 2/5

/
(Mean ratio)
(1/2)
/
(1/2 – 2/5) : (4/7 – 1/2)
1/10 1/1 4

So Required ratio = X : Y = 1/10 : 1/14 = 7:5

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ponugubati bharathi  (10 years ago)

take 1 quantity
milk in 1st vessel 4/7
milk in 2nd vessel 2/5
mixture 1/2
apply mixture alligation method
u will get 1/10 : 1/14
= 7:5

Is this solution Helpfull? Yes (1) | No   

nivethausha  (10 years ago)

consider either milk or water ...
If u consider milk :
milk be re.1 per litre.
1 lit milk mixture of A=4/7 lit; milk in 1 lit mixture of b=2/5
For c=1/2 lit.
C.p of 1 liter in A= Rs.4/7
C.p of 1 liter in B=Rs.2/5
mean price=Rs.1/2,
By the using alligation
4/7( mix.in A) 2/5( mix.in B)
/
1/2
/
1/10 1/14
[mean price- mix.B] [mix.A-mean price]
req ratio=1/10:1/4
=7:5

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Anusha  (10 years ago)

ratio of milk in A = 4/7
ratio of milk in B = 2/5
ratio of milk in C = 1/2 ,
subtract the mean value 1/2 with the ratio's 2/5,4/7
required ratio is 7:5

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RAVI VERMA  (10 years ago)

ANS IS D 14/10

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