Latest Elitmus Aptitude Question SOLUTION: Two letters are selected at random from the set of English alphabets what's the probability that 1)both are vowels? 2)both are consonants? 3)one is vowel and the other is consonant

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(#M40039267) ELITMUS Numerical Ability question Probabilty Keep an EYE

Two letters are selected at random from the set of English alphabets
what's the probability that
1)both are vowels?
2)both are consonants?
3)one is vowel and the other is consonant?

Asked In Elitmus Ankit Boae (9 years ago)

Unsolved Read Solution (17)

Is this Puzzle helpful?   (27)   (13) Submit Your Solution Permutation and Combination

Read Solution (17) :

tanuj gehlot  (9 years ago)

1) 5C2/26C2=2/65
2) 21C2/26C2= 42/65
3) (5C1*21C1)/26C2=21/130

Is this solution Helpfull? Yes (61) | No (4)  

shikhar garg  (9 years ago)

I Love You Anjana Kumari.

Is this solution Helpfull? Yes (16) | No (14)  

veer kumar  (9 years ago)

@gaurav kumar
1 and 2 are correct
but i think 3rd is wrong bcoz
event is "1 vowel and 1 consonants"
but according to ur solution it is "1 vowel or 1 consonant"
so the correct solution would be
1 vowel=(5c1)/(26c1)=5/26 and 1 consonant=(21c1)/(26c1)=21/26
and since both are inclusive
so answer will be (5/26)*(21/26)

Is this solution Helpfull? Yes (8) | No (6)  

Anjana Kumari  (9 years ago)

1) 2/65
2) 42/65
3) 21/65

Is this solution Helpfull? Yes (5) | No (2)  

gaurav kumar  (9 years ago)

1. (5c2)/(26c2)=2/65
2. (21c2)/(26c2)=42/65
3. (5+21)/(26c2)=2/25

Is this solution Helpfull? Yes (4) | No (6)  

AMIT KUMAR  (9 years ago)

1)5C2/26C2
2)21C2/26C2
3)5C1*21C1/26C2

Is this solution Helpfull? Yes (3) | No   

durga devarapu  (9 years ago)

5c2/26c2=2/65
21c2/26c2
5c1.21c1/26c2

Is this solution Helpfull? Yes (2) | No   

Anjana Kumari  (9 years ago)

1) 2/65
2) 42/65
3) 21/130

Is this solution Helpfull? Yes (2) | No   

Pranoy Bej  (9 years ago)

ANSWER==>
1. 5C2/26C2 = 10/325= 2/65
2. 21C2/26C2 = 210/325 = 42/65
3. (5C2+21C2)/26C2 = 220/325 = 44/65

Is this solution Helpfull? Yes (1) | No (11)  

sachin pal  (9 years ago)

1. (5c2)/(26c2)
2. (21c2)/(26c2)
3. (5*21)/(25*26)
this is correct

Is this solution Helpfull? Yes (1) | No   

vaibhav  (9 years ago)

1) 5C2/26C2=2/65
2) 21C2/26C2= 42/65
3) (5C1*21C1)/26C2=21/130

Is this solution Helpfull? Yes (1) | No   

NARESH KUMAR  (9 years ago)

1)Here we have to pick both vowels so,
5c2/26c2=2/65
2)Here we have to pick both consonants so,
21c2/26c2=42/65
3)Here we have to pick one is vowel and the other is consonant so,
according to question we have to perform and operation
(5C1*21C1)/26C2=21/130

Is this solution Helpfull? Yes (1) | No   

Varun Kumar Srivastava  (9 years ago)

Answer to third will be :
(5/26*21/25)+(21/26*5/25) or 2*21/26*5/25 as either of vowel or consonant can occur in the first and second selection.

Is this solution Helpfull? Yes (1) | No   

khilendra  (9 years ago)

1) (5/26)*(4/25)= 2/65

2) (21/26)*(20/25)= 42/65

3) for vowel (5/26)* for consonant (21/25)= 21/130

Is this solution Helpfull? Yes (1) | No   

santosh kumar  (7 years ago)

1) 5C2/26C2=2/65
2) 21C2/26C2= 42/65
3) (5C1*21C1)/26C2=21/65

Is this solution Helpfull? Yes (1) | No   

kollikishore  (9 years ago)

you r correct @pandey

Is this solution Helpfull? Yes | No   

prateek  (9 years ago)

1. 5c2/26c2
2. 21c2/26c2
3.5c1*21c1/26c2

Is this solution Helpfull? Yes | No   

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