Latest Gate Aptitude Question SOLUTION: there are two candidates p and q in an election.During the campaign,40% of the voters promised to vote for P ,and rest for Q.however, on the day of election 15% of the voter went b

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there are two candidates p and q in an election.During the
campaign,40% of the voters promised to vote for P ,and rest
for Q.however, on the day of election 15% of the voter went
back on their promise to vote for P and instead voted for Q.
25% of the voters went back on their promise to vote for Q
and instead voted for P.suppose,P lost by two votes,then
what was the total no. of voters.

Asked In Gate NAVEEN KUMAR (9 years ago)

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dharmendra  (9 years ago)

let X is total voters
P Get votes=.4X-(.15*.4x)+(.25*.6X)=.49X
Q Get votes=.6X-(.25*.6X)+(.15*.4X)=.51X
According to condistion
Q-P=2
.51X-.49X=2
X=100

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Ajay Kumar Gupta  (9 years ago)

let total voters=x
promised voter for P & Q are 0.4x and 0.6x respectively.
15% of P back on their promise and voted Q i.e 0.06x less in P but that no. of voters will increase in Q.25% of Q back on promise and voted P i.e 0.15x less in Q but increase in P.
i.e votes of P=0.4x-0.06x+0.15x=0.49x
votes of Q=0.6x+0.06x-0.15x=0.51x
0.49x+2=0.51x
so x=100.

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sushil Kumar  (6 years ago)

40% promised to vote for P i.e 4 votes goes to P out of 10 and thus 6 votes to Q
i.e P =4 votes as promised but 15% went back So ,
p = 4 * 85%=3.4 votes

and 4-3.4= 0.6 votes goes to Q.

now Q has 6 votes out of 10 but 25% went back
so Q= 6*75%=4.5 votes
actual Q votes =4.5+0.6=5.1 votes
actual P votes= 3.4+1.5=4.9 votes
given P -Q=2
.2=2
therefor, 1=10
therfore ,10 (initially taken as total votes) = 100 ans


Now

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