Latest Elitmus Aptitude Question SOLUTION: ASK * TO KARL OSAK TYSOL

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(#M40039351) ELITMUS Logical Reasoning question Cryptography Keep an EYE

ASK
* TO
KARL
OSAK
TYSOL

Asked In Elitmus Himanshu Bansal (9 years ago)

Unsolved Read Solution (8)

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kumari tulsi  (9 years ago)

985
*76
------
5910
6895
----------
74860

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kumari tulsi  (9 years ago)

@ vineysagar
there are few tricks by which u can solve crpt like
1 * n = n,0 * n = 0,
5*odd no = x5 ,where x can be 0,1,2,3,4
6*even no=(y)even no, where y can be 1,2,3,4

these are the only trick which i know

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kumari tulsi  (9 years ago)

sorry it's T * K=K in place of O * K=K

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vishal kumar  (9 years ago)

t*k=k
so pair of (t,k) are (6,4),(7,5),(9,5)(3,5)
try with these pair one by one
finally
with (7,5)
985*76

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Ankit Ranjan  (9 years ago)

985
*76
.............
5910
6895*
...........
74860
...........
Explanation:-
(1)T=O+1(because sum of any distinct 2 digit no. is not>=20)
(2) t*k=k therefore,either t=6,K=any even no.(except 6) or k=5
so, if you take t=6 then O=5 therefore possible values of k=2,4,8
taking all the possible values of k it will not satisfy R+K=5.
NOW, take k=5 , possible values of (T,O)={(3,2),(7,6),(9,8)}

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Moumita Das  (9 years ago)

@tulsi Can u pls explain

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kumari tulsi  (9 years ago)

In the 4th line if we see , O * K =K may have two possibilities either T=1 (1*n=n) or K=5(5*odd no=_5),but T can't be equal to 1 because if it would be 1 then the 4th line would be like ASK but according to question OSAK is given.therefore K will 5.now if K will be 5 then O will be an even no and L will be 0(because 5*even no=_0).Now O can be (2,4,6,8) and T can (3,7,9).from the last row also we get O+1(carry)=T............from these information you can find all other values.

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vineysagar  (9 years ago)

tulsi.. will u please me make me understand how u have multiplied and whats logic of cryptography.... i am totally unfamiliar with this.. plzz make me understand....

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