Latest TCS Aptitude Question SOLUTION: how many ways does 10 pencils given to four children such that each get atleast 1?

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(#M40039394) TCS Numerical Ability question Keep an EYE

how many ways does 10 pencils given to four children such that each get atleast 1?

Asked In TCS manaswini devabhakthuni (9 years ago)

Unsolved Read Solution (24)

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Read Solution (24) :

karthikeyank  (9 years ago)

Ans is:84
(10-1)C(4-1)=9C3=9*8*7/3*2=504/6=84

Is this solution Helpfull? Yes (44) | No (4)  

Sourav ganguly  (9 years ago)

There are 10 pencils
so 1 given to each
hence 6 remains
as per product rule and sum rule the total ways will be
4*(6+5+4+3+2+1)=84

Is this solution Helpfull? Yes (14) | No (1)  

karthikeyank  (9 years ago)

Formula is (n-1)C(r-1)

Is this solution Helpfull? Yes (12) | No (3)  

karthikeyank  (9 years ago)

Number of ways of distributing n identical things among r person where Each person get atleast one...

Is this solution Helpfull? Yes (8) | No (1)  

ashish  (9 years ago)

in which case we use this formula..? only when we have to distribute atleast one to all ?

Is this solution Helpfull? Yes (1) | No (1)  

Saranya .C  (9 years ago)

@karthikeyank plz explain

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shashi kumar  (9 years ago)

(10-1)C(4-1)

Is this solution Helpfull? Yes (1) | No (1)  

shiv kumar sharma  (9 years ago)

pencils are same and 1 children get 1 pencil
remaining pencils are 6
so
1c=6pcncils
2c=6pencils
3c=6pencils
4c=6pencils
answer is 6^4=1296

Is this solution Helpfull? Yes (1) | No (8)  

Rupen Raj  (9 years ago)

4^10
1 pencil can be given to 4 children in 4 ways.
similary 10 pencils in 4^10

Is this solution Helpfull? Yes (1) | No (3)  

neha kumari  (9 years ago)

(10-1)C(4-1)=84

Is this solution Helpfull? Yes (1) | No   

ashish  (9 years ago)

@karthikey- plz explain the solution, and how to use this formula

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Shashi Shekhar  (9 years ago)

@Karthik
plz explain the answer

Is this solution Helpfull? Yes | No (1)  

Saranya .C  (9 years ago)

i think ans is 10C4

Is this solution Helpfull? Yes | No (7)  

saurabh kumar  (9 years ago)

note:if pencil are similar.
first give 1 pencil to each children.
now as 6 pencil are remaining.
now 1st pencil out of 6 can be given to any 4 children i.e. there are four ways to give 1 pencil to 4 children.
-->similarly, 2nd pencil can be given to any of 4 children.. and so on..upto 6th pencil.
thus we get 4^6 ways .
which is 4^6=256.

Is this solution Helpfull? Yes | No (5)  

Ninad Raikwar  (9 years ago)

(n-1)C(r-1)
Its a concept we use when u have to distribute n similar item between r persons such that all get at least 1. So. 9C3

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raviteja  (9 years ago)

can any one say without using formulae?????

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vivek kumar  (9 years ago)

number of ways distributing n identical things among p groups so that atleast each get one = (n-1)c(p-1)
so ways= 9c3

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Suneet Tangallapally  (9 years ago)

(10-1)C(4-1)=9C3=84

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ANIL YADAV  (9 years ago)

distribution of n things in n numbers hat every one get atleast one item =
(n-1)C(r-1)
so we get (10-1)C(4-1)=84

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sanyogita holkar  (9 years ago)

if we give 1 pencil to four children ... after that 6 pencils are remaining .... thus .. we can ditribute .. these in ..= 6*6*6*6=256 ways..

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akshita  (9 years ago)

10c4-4c2/10c4

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aiyaz sarwar  (9 years ago)

plz explain clearly

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Pratik sharma  (9 years ago)

(10-1)C(4-1)=84

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Vishal Bhattacharjee  (9 years ago)

(n-1)C =9C3
(r-1)

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