Latest IBM Aptitude Question SOLUTION: 1) 1/4, 1/4, 1/2, 3/2, 6, ? 2) 0.8, 1.8, 3.6, 3.6, 4.6, 9.2, 9.2, 10.2, ? 3) 22, 19.5, 21.45, 33, 30.5, 33.55, 44, 41.5, ? 4) 15 3/4, 16, 26, 9 1/5, 9, 19, 64 2/3, 65, 75, 30 3/

1) 1/4,1/4,1/2,3/2,6,x
(1/4)*1 =1/4 (Second term)
(1/4)*2 =1/2 (Third term)
(1/2)*3 =3/2 (Fourth term)
(3/2)*4=6 (Fifth term)
6*5=30 (Sixth term) Ans

2) 0.8,1.8,3.6,3.6,4.6,9.2,9.2,10.2,x

Grouping in threes we get
(0.8,1.8,3.6)(3.6,4.6,9.2)(9.2,10.2,x)
0.8+1=1.8
1.8*2=3.6
Third term of first group is the first term of second group
Similarly
3.6+1=4.6
4.6*2=9.2
Third term of second group is the first term of third group
Similarly
9.2+1=10.2
10.2*2= 20.4(Ans)

3) 22,19.5,21.45,33,30.5,33.55,44,41.5,x

Grouping in threes
(22,19.5,21.45)(33,30.5,33.55)(44,41.5,x)
First group
22-19.5=2.5
22-21.45=0.55
Second Group
33-30.5=2.5
33-33.55=0.55
Third Group
44-41.5=2.5
x-44=0.55
x=44+0.55=44.55 (ANS)

4)15 3/4,16,26,9 1/5,9,19,64 2/3,65,75,30 3/8

Grouping in threes we get
(15 3/4,16,26)(9 1/5,9,19)(64 2/3,65,75) (30 3/8,x,y)

Second term in each group is obtained after rounding off the first term in the same group
Second term+10=Third term
15 3/4 becomes 16
16+10=26
Similarly
30 3/8 becomes 30(since the fraction 3/8 gives 0.375 which is less than 0.5)
30+10=40 Ans=30

6) 3/2,2 1/4,9/4,7/2,12 1/4,49/4,4/3,1 7/9,16/9
3/2,9/4,9/4,7/2,49/4,49/4,4/3,16/9,16/9
Grouping in threes
(3/2,9/4,9/4) (7/2,49/4,49/4) (4/3,16/9,16/9) (x,y,z)
(Numerator+4)/Denominator=first term of second group
(3+4)/2=7/2
similarly
(4+4)/3=8/3 Ans

7) 18,24,5,21,27,8,17,23,4,24,30,x
Grouping in threes
(18,24,5) (21,27,8) (17,23,4) (24,30,x)
18+6=24
24-5=19
Also,
21+6=27
27-8=19
similarly
24+6=30
30-x=19
x=11 ANS

8)100,98,95,90,83
100-98=2
98-95=3
95-90=5
90-83=7
83-x=11(11 is the next prime number)
x=72 (Ans)

9)1,3,3,2,8,10,3,4,12,4,8,x
Grouping in threes
(1,3,3)(2,8,10)(3,4,12)(4,8,x)
First group 1*3=3 (Third term)
Second group 2+8=10 (Third term)
Third group 3*4=12(Third term)
Fourth Group 8+4=12 (Third term)Ans

10) 49,7,98,16,4,48,9,3,36,25,5,x
Grouping in threes
(49,7,98) (16,4,48)(9,3,36)(25,5,x)

49*2=98
16*3=48
9*4=36
25*5=125 ANS
11) (9,12,4,8)(12,15,5,9)(3,6,2,6)(6,9,X,Y)
9+3=12/3=4+4=8
12+3=15/3=5+4=9
6+3=9/3=3+4=7
Ans 3
12) 5/6, 1/3, 1/2, 1/2, 2/8, 1/4, 5/6, 1/6, 2/3, 1/2, 1/3, ?
Grouping in three
(5/6 ,1/3, 1/2) (1/2,2/8,1/4) (5/6, 1/6, 2/3)(1/2,1/3,x)
First term -second term=Third term
1/2- 1/3= 1/6 ANS

13) 33,8,41,46,21,67,72,47,119,124,x
Grouping in threes
(33,8,41) (46,21,67)(72,47,119)(124,x,y)
8,21,47,x
21-8 =13
47-21=26
x-47=39
x=86 (ANS)
14) 1/7 ,3/4, 4/9,5/6,7/11,7/8

Series 1 = 1/7 , 4/9, 7/11

1+3 = 4
7+2 = 9
4+3 = 7
9=2 = 11
7+3 = 10
11+2 = 13
10/13 ANS

15)7,4,6,3,4.5,1.5,2.25,-0.75,x


7-4 = 3
6-3 =3
4.5-1.5 = 3
2.25-(-0.75) = 3
Also,
7,6,4.5.2.25

7-1 = 6
6-1.5 (1*1.5) = 4.5
4.5-2.25(1.5 *1.5 ) = 2.25
then

2.25 - (2.25 * 1.5 ) = -1.125

5) 3,(2,1),4,(5,4),5,(1,0),6,(3,?)
Ans:2

3)22, 19.5, 21.45, 33, 30.5, 33.55, 44, 41.5, ?
22,19.5,21.45
33,30.5,33.55
44,41.5,45.65

1.1/4*1=1/4
1/4*2=1/2
1/2*3=3/2
3/2*4=6
6*5=30

2.1.8-0.8=1.0
1.8*2=3.6
1.8*2=3.6
4.6-3.6=1.0
4.6*2=9.2
4.6*2=9.2
10.2-9.2=1.0
10.2*2=20.4
10.2*2=20.4

5.3+2-1=4
4+5-4=5
5+1-0=6
6+3-2=7.....

11) 9+3=12
12/3=4
4+4=8

12+3=15
15/3=5
5+4=9


3+3=6
6/3=2
2+4=6


6+3=9
9/3=3
so 3 is the ans i guess.

4)15 3/4,16,26,9 1/5,9,19,64 2/3,65,75,30 3/8
15+1=16,16+10=26
9+0=9,9+10=19
64+1=65,65+10=75
30+0=30,30+10=40
so,nxt terms are 30,40

10) 49, 7, 98, 16, 4, 48, 9, 3, 36, 25, 5, ?
7*7=49 49*2=98
4*4=16 16*3=48
3*3=9 9*4=36
5*5=25 25*5=125

8) 100-98=2
98-95=3
95-90=5
90-83=7
all these are prime numbers, so next prime no is 11
so, 83-11=72
ans 72

9)1*3=3
2+8=10
3*4=12
4+8=12
ans=12

3.)
there r two series
22 - 0.55 = 21.45
33 + 0.55 = 33.55
44 - 0.55 = 43.45

and

19.5 +11 = 30.5
30.5 +11 = 41.5

and there is a difference of 2.5 after 22,33,44

1)30
2)20.4
3)45.65
4)3.25
6)question mistake(i think we have to change 1 1/7 to 1 7/9 the series follows)
then answer will be 8/3
7)9
8)94
9)12
10)125

7) (18,24,5) (17,23,4) = here one is decremented in each element
(21,27,8) (24,30,?)= here three is incremented in each element
so ans is 11

12)

5/6,1/3,1/2
1/2, 1/2, 2/8
like this



5/6 = 1/3 +1/2
1/2 = 2/8 + 1/4
5/6 = 1/6 +1/3
1/2 = 1/3 +1/6

answer 7)
given series 18,24,5,21,27,8,17,23,4,24,30,?

take a group of triplet
take the corresponding difference
e.g
21-18 = 3
27-24 = 3
8-5 =3

17-21 = -4
23-24 = -4
4-8 = -4

24-17 = 7
30-23 = 7
ans - 4 = 7

=> ans = 7+4=11

the missing no. is 11

12) 1/6
Consider the series as
A , B , C
where 3rd term is given by
A - B = C
5/6 - 1/3 = 1/2
1/2 - 2/8 = 1/4
5/6 - 1/6 = 2/3
so
1/2 - 1/3 = 1/6

3) 22-2.5=19.5
19.5+1.95=21.45
33-2.5=30.5
30.5+3.05=33.55
44-2.5=41.5
41.5-4.15=45.65
so ans is 45.65

8)100-2=98
98-3=95
95-5=90
90-7=83
83-9=74
ans=74

answer for 15)
series 7,4,6,4.5,2.25,-0.75, ?
difference between all the pairs from starting is 3
i,e. 7-4 = 6-3 = 4.5-1.5 = 2.25-(-0.75) = 3

now take the difference of pairs starting from the 2nd number
6-4 = 2
4.5-3 = 1.5
2.25-1.5 = 0.75 (equation b )

so how this came,
finding the relation of 1.5 from 2
3-2 = 1, 1/2 = 0.5
2-0.5 = 1.5

similarly for 0.75 from 1.5
3-1.5 = 1.5 , 1.5/2= 0.75
1.5-0.75 = 0.75

so the next difference will be,
3-0.75 = 2.25, 2.25/2 = 1.125
0.75-1.125 = -0.375

ans - (-0.75) = -0.375 ....( applying equation b)
ans = -0.75 - 0.375
= -1.125

so the missing no. will be -1.125

5) 3 2 1 4 5 4 5 1 0 6 3
3 4 5 6
2, 2+3=5, 5-4=1, 1+2=3
1, 1+3=4, 4-4=0, 0+2=2

22, 19.5, 21.45, 33, 30.5, 33.55, 44, 41.5, ?
-2.5 -.55 -2.5 +.55 -2.5 -.55
so,ans is 44-.55=43.45

63/4,16,26--->16*4-1=63
46/5,9,19---->9*5+1=46
194/3,65,75--->65*3-1=194
244/8,30,40--->30*8+1=244
so ans is 30
or
15+1=16
9+0=9
64+1=65
30+0=30

7)

24-18 = 6
27 - 21 = 6
23 - 17 = 6
30- 24 = 6

and
5 +3 =8
8 - 4 = 4
4 +5 =9
so 9 should come

15)

7-4 = 3
6-3 =3
4.5-1.5 = 3
2.25-(-0.75) = 3

and how

7,6,4.5.2.25

7-1 = 6
6-1.5 (1*1.5) = 4.5
4.5-2.25(1.5 *1.5 ) = 2.25
then

2.25 - (2.25 * 1.5 ) = -1.125

question 13)
33,8,41,46,21,67,72,47,119,124,?
Take a group of 3 i.e.
(33,8,41) (46,21,67) (72,47,119) (124,x,y)
now let the 1st, 2nd and 3rd term of each group is a,b,c respectively.
follow the pattern: a+b=c and a-b=25 (for each group)
so 124-x=25 and 124+x=y
so x=99 (answer) and y=124+99=223(it is not required as per the question)

could anyone please share the english paper for IBM?
MY email id: bhargavreddy1011@gmail.com

7)18,24,5
21,27,8
17,23,4
24,30,_
sol:(18+3=21,24+3=27,5+3=8)
similarly (24-4,27-4,8-4)=17,23,4
(17+7=24,23+7=30,4+7=11)
so 11 is the solution

somebody plz give solution of question 11

http://www.m4maths.com/17622-9-12-4-8-12-15-5-9-3-6-2-6-6-9.html answer of question number 11

14) 1/7,3/4,4/9,5/6,7/11,7/8

Series 1 = 1/7 , 4/9, 7/11

1+3 = 4
7+2 = 9
4+3 = 7
9=2 = 11
7+3 = 10
11+2 = 13
Therefore, 10/13 is one number

Series 2 = 3/4 , 5/6 , 7/8

3+2 = 5
4+2 = 6
5+2 = 7
6+2 = 8
7+2 = 9
11+2 = 13
Therefore, 9/10 is the other number

14){1/7,4/9,7/11}
{3/4,5/6,7/8}
two mix serise are there so next term will be
(7+3)/(11+2)=10/13

0.8+1=1.8
1.8+1.8=3.6
.
.
10.2+10.2=20.4

1)1/4*1=1/4
1/4*2=1/2
1/2*3=3/2
3/2*4=6
6*5=30
so ans is 30

can anyone can explain the 13th question plzzzzz

11) first we have to divide the series as
(9 ,12,4,8)
(12,15,5,9)
(3 ,6 ,2,6)
(6 ,9 ,x,y)
9-1 =8
12-9=3
3+6 =9

(5) 3,(2,1),4,(5,4),5,(1,0),6,(3,*) so answer is 2.

explain question no 6 plz