Latest A website Aptitude Question SOLUTION: If 378 coins consists of rupees, 50 paise and 25 paise coins, whose values are in the ratio 13 : 11 : 7, the number of 50 paise coins will be (a) 132 (b) 128 (c) 136 (d) 133

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(#M40040018) A WEBSITE Numerical Ability question Keep an EYE

If 378 coins consists of rupees, 50 paise and 25 paise coins, whose values are in the ratio 13 : 11 : 7, the number of 50 paise coins will be
(a) 132 (b) 128
(c) 136 (d) 133

Asked In A website lakshmi nalluri (9 years ago)

Solved khushboo goenka Read Solution (3)

Is this Puzzle helpful?   (50)   (13) Submit Your Solution Co-ordinate geometry

Read Solution (3) :

BHASKAR MANDAL  (9 years ago)

let the no. of 25 paise be - x
50 - y
1 rupee -z

so we can write,
(0.5*y)/(0.25*x) = 11/7
=> y = 11/14 x ......(i)

again for 1 rupee and 25 paise
(1.0 *z)/(0.25*x) = 13/7 ...(ii)
=>z = 13/28
total no. of coins
x+y+z = 378
x(1+(11/14)+(13/7))=378
x=168

so the number of 50 paise
y = (11/14)*168 = 132

so option a is the answer

Is this solution Helpfull? Yes (5) | No (2)  

khushboo goenka  (9 years ago) Best Solution

132
coz 50 paise are in the ratio of 11
and 132 =11*12

Is this solution Helpfull? Yes (4) | No (5)  

Mayank Kumar  (7 years ago)

answer is A
only 132 is divisible by 11

Is this solution Helpfull? Yes | No (4)  

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