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(#M40040210) ELITMUS Numerical Ability question geometry Keep an EYE

what is the max number of cone that can be cut from the cuboid of dimension 24*16*9.If the base of the cone is on one of the face of cuboid.

Asked In Elitmus Shio Shanker Awasthi (10 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

abhayam  (9 years ago)

ans is 8

First we will find the min volumeof cone that can be made from given cuboid,in this way we can get the maximum number of cones that can be cut(cone of smallest volume).

for this
r=max(24,16)/2 r=12 ,h=9 volume=432pi
r=max(9,16)/2 r=8,h=24 volume=512pi
r=max(24,9)/2 r=12,h=19 volume=768pi


take the minimum of volume i.e 432pi


Volume of cuboid=l*b*h=3456
max number of cones required are = volume of cuboid/volume of cone of minimum volume

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aquib aslam  (10 years ago)

r=8 and h=9
phi r^2h we get the ans a

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Shio Shanker Awasthi  (10 years ago)

are yaar explain to karo

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Supriya Mahanto  (7 years ago)

Only restriction given is that base of the cone should be on one of the face of cuboid. Since there are no other restrictions, any value of the base radius is possible such as r=1, 2, 0.2, 0.01 etc because all such bases can be on one of the face of cuboid. Theoretically, infinite number of cones can be cut.

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akash verma  (10 years ago)

r =8 and height == 24

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vikash kumar  (10 years ago)

1024*128+256*2+10===
1024=4^5;
128=4^3 * 2;
256==4^4 ;

then
4^5 * 4^3 *2 +4^4 * 2 + 4 * 2 + 2 then
4^8 * 2 + 4^4 * 2 + 4*2 + 4^0 * 2 then
20002022

then right ans is 4

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Puja  (10 years ago)

please explain Vikash

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swati priya  (10 years ago)

explain please

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