Latest Elitmus Aptitude Question SOLUTION: total egg sold by shopkeeper if third day there he sold all eggs a) each day he sold half of total eggs + 1/2 an egg b) no one purchase half an egg

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(#M40040375) ELITMUS Logical Reasoning question data sufficiency Keep an EYE

total egg sold by shopkeeper
if third day there he sold all eggs
a) each day he sold half of total eggs + 1/2 an egg
b) no one purchase half an egg

Asked In Elitmus kumar (9 years ago)

Unsolved Read Solution (14)

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Read Solution (14) :

darshana kumrawat  (9 years ago)

if x be total no. of eggs
then on 1st day eggs sold x/2+1/2, remaining x/2-1/2
on 2nd day eggs sold = 1/2(x/2-1/2)+1/2 = x/4 + 1/4, remaining x/4 - 3/4
on third day eggs sold = 1/2(x/4-3/4) + 1/2 = x/8 + 1/8

x/2+1/2+x/4+1/4+x/8+1/8=x
thus x=7
first day 3.5 + .5=4
second day 1.5 + .5 =2
thirsd day .5 + .5= 1
total 7

Is this solution Helpfull? Yes (24) | No (2)  

kumar  (9 years ago)

@durgesh kumar
bro it is possible using 1st statement only

third day he sold half the eggs + half an egg and all eggs finished
that is possible only if last day he have only one egg
half of eggs + half an egg=0.5+0.5=1 egg
mean 2nd last day he sold =1.5+.5=2 eggs (since last day he had
half less than half egg mean he has 3 eggs )
now 1st day he sold =3.5+.5 =4 eggs (since last day he had
half less than half egg ,and 2nd day he has total 3 eggs , mean he has 7 eggs in third day )

so total number of eggs =7

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kumar  (9 years ago)

sorry previous wale me thora explanation clear nahi likha so go through this one

@durgesh kumar
bro it is possible using 1st statement only

third day he sold half the eggs + half an egg and all eggs finished
that is possible only if last day he have only one egg
half of eggs + half an egg=0.5+0.5=1 egg

mean 2nd last day he sold =1.5+.5=2 eggs (since last day he had
half less than half egg since 2nd day he sold half the eggs + half an egg mean he has 3 eggs )

now 1st day he sold =3.5+.5 =4 eggs (since 2nd day he had
half less than half egg ,and 2nd day he has total 3 eggs , mean 3rd day he has 3+0.5+0.5 mean he has 7 eggs in third day )

check in reverse order also ,you will get same ans

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raja babu singh  (9 years ago)

LET eggs = x;
day sold remaining
1 x/2+1/2 x/2-1/2
2 ( x/2-1/2)/2+1/2 ( x/2-1/2)/2-1/2
3 ( ( x/2-1/2)/2-1/2 )/2+1/2 o
on 3rd day total sold egg=1;
then ( ( x/2-1/2)/2-1/2 )/2+1/2 =1;
x=7;

Is this solution Helpfull? Yes (4) | No (3)  

Durgesh Kumar  (9 years ago)

both are insufficient to answer the question.because total amount of egg is unknown.

Is this solution Helpfull? Yes (3) | No (8)  

sorox  (9 years ago)

10 me se 5 gai +.5
4 mei se 2 +.5
2 mei se 1 +.5.....................ans 10

Is this solution Helpfull? Yes (2) | No (4)  

sravani  (9 years ago)

only statement a can give the solution...

Is this solution Helpfull? Yes (1) | No   

maharaja  (9 years ago)

koi bhi nahin samjh aaya...

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Akash Dutta  (9 years ago)

let there be x eggs at the start.
first day: x/2+1/2=(x+1)/2
second day: (1/2*(x+1)/2)+1/2=x/4+1/2=(x+3)/4
third day: (1/2(x+3)/4)+1/2=(x+3)/8+1/2=(x+7)/8
x=(x+1)/2+(x+3)/4+(x+7)/8=(7x+17)/8
therefore: x=17

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akriti   (8 years ago)

total 7 egg

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keerthana chennamsetty  (8 years ago)

please can you provide options for this?

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Akshita srivastava  (8 years ago)

a is enough to answer the question

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chandan kumar  (8 years ago)

(7/2+1/2)+(3/2+1/2)+(1/2+1/2)=7 eggs

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chandan kumar  (8 years ago)

7 eggs

day 1st 7/2+1/2 remaining is 3
day 2nd 3/2+1/2 remaining is 1
day 3rd 1/2+1/2 remaining 0

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