Latest TCS Aptitude Question SOLUTION: A two digit number is 18 less than the sum of the squares of its digits. How many such numbers are there

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A two digit number is 18 less than the sum of the squares of its digits. How many such numbers are there

Asked In TCS PARUL JOSHI (10 years ago)

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Aditya keri  (10 years ago)

Only two possible numbers are :
47
and
67

The equation would be :
10x + y = (x^2) + (y^2) - 18
Substitute different values from the options.

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lakhan jalodiya  (10 years ago)

let no be 10x + y
now 10x + y =x^2 + y^ 2+ 18
the possible ans are 47 n 67

Is this solution Helpfull? Yes (1) | No (3)  

Prakash kumar Pariari  (10 years ago)

ans=2 63 and 82

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aman  (10 years ago)

Take N = 10a+b.
Given that, 10a+b+18 = (a+b)2
for a = 1 to 9, the L.H.S. will be, 28+b, 38+b, 48+b,.....,108+b.
As LHS is perfect square for the values of b = 1 to 9, only 28+b, 48+b, 58+b, 78+b can be equal to 36, 49, 64, 81 for b = 8, 1, 6, 3 respectively. But only 78+b = 81 for b = 3 So only one such number is possible. I.e, 63

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