Latest CSC Aptitude Question SOLUTION: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the

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There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

A. 20
B. 80
C. 100
D. 200

Asked In CSC (12 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

Dr.Dipin Singh  (12 years ago)

A has 100 students and B has 80students.

If a is no of students in A and b is no of students in B, then

a-10 = b+10
a+20 = 2*(b-20)

solving these eqns, we get
a=100

Is this solution Helpfull? Yes (7) | No (2)  

Dr.Dipin Singh  (12 years ago)

B. 80

A has 80 students and B ahs 70 students.

If a is no of students in A and b is no of students in B, then

a= b+10
a+20 = 2*(b-20)

solving these eqns, we get
a=80

Is this solution Helpfull? Yes (3) | No (6)  

Vinay  (12 years ago)

answer will be 100.
dipin chech ur 1st equation
it shod be like ...
a-10=b+10
................i may wrong but who ever c answer please tell solution

Is this solution Helpfull? Yes (2) | No (2)  

yogakh  (9 years ago)

Let number of students in room A and B be a and b respectively.
data1: If 10 students are sent from A to B, then the number of students in each room is the same =>(a-10)=(b+10)
=>a-b=20..................1
data2:If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B=> a=2 times b i.e.,(a+20)=2(b-20)
=>2b-a=60..............2

substitute a=b+20 in eq.2=>2b-b-20=60
=>b=60+40=80.

we know that a-b=20 from eq.1=>a=80+20=100.
hence, a=100 , b=80.

Is this solution Helpfull? Yes (1) | No   

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