Latest Elitmus Aptitude Question SOLUTION: A triangle of side 10,17,21.a square in the triangle whose two corner touch tow side of triangle & one side of square on biggest side of triangle side. find out side of square?? (a

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(#M40041304) ELITMUS Numerical Ability question Keep an EYE

A triangle of side 10,17,21.a square in the triangle whose two corner touch tow side of triangle & one side of square on biggest side of triangle side. find out side of square??
(a)5.4 (b)5.8 (c)6.7 (d)7.2

Asked In Elitmus Surendra Kumar Sharma (9 years ago)

Unsolved Read Solution (3)

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Read Solution (3) :

javed iqbal  (9 years ago)

first find the area using the heros formula
A=sqrt[(s)(s-a)(s-b)(s-c)]
A=sqrt[24*14*7*3]
A=sqrt[7056]
A=84

now if you name the triangle PQR with PQ=10 QR=21 PR=17
and then draw a perpendicular from P to the side QR and name it PM

now you can find the height of the triangle PQR by
1/2 * base * height= Area(by heroes formula)
1/2 * 21 * h =84
h= 8

if u imagine the two edges of square touching the sides of triangle let that be A on side PQ and B on side PR
and the perpendicular PM cutting AB @ C
now let the side of square be = x cm total height of PQR = 8
then height of triangle PAB is PC=8-x


the the triangle PAB is similar to triangle PQR

then AB/QR=PC/PM
x/21=8-x/8
8x=168-21x
29x=168
x=168/29
x=5.79 ~ 5.8 cm

Option B ok
any problem contact me @ iqbalj6303@yahoo.co.in

Is this solution Helpfull? Yes (36) | No (1)  

javed iqbal  (9 years ago)

if any problem in the solution i explained plz refer to this link

http://www.qbyte.org/puzzles/p076s.html

Is this solution Helpfull? Yes (12) | No   

Anuj Gupta  (7 years ago)

a=10,b=21,c=17
s=(a+b+c)/2
s= 48
area (heroins formula) = 3 * 8 * 7 *2*3
area = b*h/2
h= area * 2 /b
= 8

side of square = (b * h)/ (b+h)
= 21 * 8 /(21 +8)
= 5.79 ~ 5.8

Is this solution Helpfull? Yes (2) | No   

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