Latest Infosys Aptitude Question SOLUTION: A man sold two cows for Rs. 210 at a total profit of 5 %. He sold one cow at a loss of 10% and another at a profit of 10%. What is the price of each cow?

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A man sold two cows for Rs. 210 at a total profit of 5 %. He sold one cow at a loss of 10% and another at a profit of 10%. What is the price of each cow?

Asked In Infosys (12 years ago)

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prakash jha  (10 years ago)

50 and 150
after profit, price is 210
so cost price of 2 cows = 200
x+y=200
selling price of 2 cows =210
0.9x + 1.1y =210 //1 cow sold at 10 % loss and another is at 10% profit
solving both equations x=50 and y=150

Is this solution Helpfull? Yes (20) | No   

Dasari Gopi  (10 years ago)

50 and 150
after profit, price is 210
so cost price of 2 cows = 200
x+y=200
selling price of 2 cows =210
0.9x + 1.1y =210 //1 cow sold at 10 % loss and another is at 10% profit
solving both equations x=50 and y=150

Is this solution Helpfull? Yes (2) | No (2)  

sama  (9 years ago)

50 and 150
after profit, price is 210
so we calculate cost price follows
(210*5)/100 which is approx 200
so now cost price is 200
x+y=200---> (1)

now make another equation
take the selling price of cows- 210
and cost price is 200
so profit is rs10
from this rs10 there is 10% profit for 1 cow and 10% profit for other cow
so calculate each loss and profit
loss- (10*10)/100=1
loss%= ((10-1)*10)/100= 0.9
same way finf profit %
profit- (10*10)/100=1
loss%= ((10+1)*10)/100= 1.1
and now make the equation
0.9x+1.1y=210
solving both equations we get
x=50 and y=150

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nishu jindal  (11 years ago)

50 and 150

Is this solution Helpfull? Yes | No (5)  

RUPA KUMARI  (9 years ago)

50and 150

Is this solution Helpfull? Yes | No (2)  

Amaresh Sahoo  (9 years ago)

CP=200,suppose one part is X and second is 200-X.
one part wii sell at 0.9X and other at 1.1(200-X).
then 0.9X+1.1(200-X)=210 ....
so x=50 and other is 150

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