Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20

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(#M40000429) TCS Numerical Ability question Keep an EYE

Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is
a) 4
b) 3
c) 1
d) 0: Asked In TCS karthikeyan (13 years ago); Solved Read Solution (9); Is this Puzzle helpful? (11) (2) Submit Your Solution Arithmetic

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Latest TCS Aptitude Question SOLUTION: Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is a) 4 b)