Latest Athenahealth Aptitude Question SOLUTION: How many numbers can be formed by using digits 0 to 9, as the number should be divisible by 5 and it should be 4 digit one and no repitation is allowed on digits?

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How many numbers can be formed by using digits 0 to 9, as the number should be divisible by 5 and it should be 4 digit one and no repitation is allowed on digits?

Asked In Athenahealth Sarabeshwar (9 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

praveen kumar  (9 years ago)

For a number to be divisbly by 5 we have two choices 0 or 5

case 1 : when choice is 0
_ _ _ 0 first digt can be filled in 9ways , 2nd in 8 ways, 3rd in 7 ways so 9 * 8 *7 = 504
case 2 : when choice is 5
_ _ _ 5 first digi can be in 8 ways (since 0 cannot come ) , 2nd in 8 ,3rd in 7 so 8*8*7 = 448

so it can be in 504 + 448 = 952 ways

Is this solution Helpfull? Yes (41) | No (8)  

niranjan  (9 years ago)

8p3 for 1st 3 digits =336
2p1 for last digit =2
result =336*2 =672

Is this solution Helpfull? Yes (11) | No (12)  

INDHUMATHI  (9 years ago)

_ _ _ _:4th digit 0 or 5 so , 2P1=2
3rd digit has 9 ways i.e) 9P1=9
2nd digit has 8 ways i.e) 8P1=8
1st digit has 7 ways i.e) 7P1=7
result=9*8*7*2=1008

Is this solution Helpfull? Yes (4) | No (3)  

vinayak  (9 years ago)

Total numbers can be formed are==> 9*9*8*7
9*9*8*7-((9*8*7)+(8*8*7))

Is this solution Helpfull? Yes (3) | No (1)  

jayanthi  (9 years ago)

frds.dont get confused.praveen kumar is absoluetely correct.nice ans praveen..

Is this solution Helpfull? Yes (3) | No   

jayakarthi K R  (9 years ago)

9p3 ie...9*8*7=504

Is this solution Helpfull? Yes (1) | No (5)  

Balaji  (9 years ago)

630 numbers can be formed

Is this solution Helpfull? Yes | No (1)  

Premlatha  (9 years ago)

4-digits->!@#$
$ can have oly 2 ways (0 or 5) = 2
! can have 8 ways since we have taken off 0 and 5 hence we have 8
@ can have 7 ways
# can have 6 ways

Hence we have 8*7*6*2 ways = 672 ways

Is this solution Helpfull? Yes | No (3)  

Kannan Mohan  (8 years ago)

ANS : 952
4 digit number from 1000 to 9999
4th digit must be 0/5 So 2 possibilities
If 4th digit is 0
1st as 9, 2nd has 8 and 3rd digit has 7 possibilities
If 4th digit is 5
1st as 8(0 would turn it into 3 digit number), 2nd has 8 and 3rd digit has 7 possibilities

So possibilities = 9*8*7+8*8*7=56*17=840+112=952

Is this solution Helpfull? Yes | No   

Athira  (8 years ago)

unit digit can be 5 or 0 : 2 ways
rest 3 ways can be filled in 9*8*7
ans 9*8*7*2=1008

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