Latest exam Aptitude Question SOLUTION: tan^2([pi]/2-[theta])csc^2[theta]+csc^2[theta]=1/sin^4[theta] can you help me verify if this is correct

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(#M40043848) EXAM Numerical Ability question Keep an EYE

tan^2([pi]/2-[theta])csc^2[theta]+csc^2[theta]=1/sin^4[theta] can you help me verify if this is correct

Asked In exam (10 years ago)

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