Latest Elitmus Aptitude Question SOLUTION: find greatest 4 digit no when divided by 10,15,22 leaves remainder of 4 ,9,10respectively.........no is written in d form of ABCD ,........find d value of BC? a.76 b.88

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(#M40044217) ELITMUS Category question Keep an EYE

find greatest 4 digit no when divided by 10,15,22 leaves remainder of 4 ,9,10respectively.........no is written in d form of ABCD ,........find d value of BC?
a.76 b.88 c.95 d.89

Asked In Elitmus PANKAJ KUMAR (10 years ago)

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AMIT KUMAR  (10 years ago)

Ans-C) 95.
Explanation- For divisibility by 10 to leave remainder 4 , unit digit should be 4.
For divisibility by 15 to leave remainder 9 , unit digit should be 4 or 9.
For divisibility by 22 to leave remainder 10 , (sum of digits at odd places) - (sum of digit at even places) = 1.
So let our no be ABC4.
So (A+C) - (B+4) = 1 (For divisibility by 22 to leave remainder 10).
Now check by option.
eg) By option c) (A+5) - (9+4)=1 Here B=9 and C=5 from option. Hence A=9.

So no becomes 9954 which is the greatest 4 digit no.

Check other options also but that will not be the greatest no.

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aman  (10 years ago)

d - 89
10 |x
15 |y-4
22 |z-9
| 1- 10

z=22+10=32
y= 15*z+9=15*32=489
x= 10*y+4=10*489+4=4894
so value for BC is 89

Is this solution Helpfull? Yes (7) | No (5)  

UJJWAL SOGANI  (10 years ago)

this is the simple hcf & lcm question
by the question let N is the digit
so N=10a+4........(1)
N=15b+9........(2)
N=22c+10......(3)
in euestion 3 put the value of a=1,2,3,4,5........
so N=32,54,76.....
this process follow by equ. 1 & 2
by 2nd N=23,39,54.....
by 1st N=14,24,34,44,54
we see 1st common is 54
so by lcm concept N=54+LCM of (10,15,22)z
so N=54+330z
we want highest 4 digit number so put z=20
N=54+(330*20)
n=9954
so answer is c -95

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kshitij kesari  (10 years ago)

c)95
on dividing 10 it gives 4 remender so last digit is 4.
on dividing with 22 and last digit is 4 so 2nd last digit is 5
now check for options with greatest 4 digit number 9954 and verify the condition

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Sunil Kumar  (10 years ago)

Ans-
Let a = 10b+4 and b = 15c+9 and c = 22d+10
on solving sec and third eqn
b = 330d+159
on solving first and new eqn
a = 3300d + 1594
so put d=0,1,2,3,4... to find d ans
So Ans is 94

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vrao  (10 years ago)

first go through the options first you select highest option and you can dived each number

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