Latest IBM Aptitude Question SOLUTION: When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ? A. 339 B. 349 C. 369 D. Data inadequate

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When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ?
A. 339 B. 349
C. 369 D. Data inadequate

Asked In IBM (12 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Techie  (9 years ago)

Don't know the exact way. But here it is.. :P Plz chk it out!
Let x be the number.
We know x/13 remainder is 11
And x/17 remainder is 9
In place of x i have divided by using the given data's.
so 349/13 gives the remainder 11 and 349/17 gives the remainder 9
And the answer must be B)349

Is this solution Helpfull? Yes (7) | No   

Poorva  (9 years ago)

Go through the options...

Is this solution Helpfull? Yes (3) | No   

BALENDU KUMAR  (7 years ago)

x = 13p + 11 and x = 17q + 9

13p + 11 = 17q + 9

17q - 13p = 2

q = 2 + 13p
17
The least value of p for which q = 2 + 13p is a whole number is p = 26
17
x = (13 x 26 + 11)

= (338 + 11)

= 349

Is this solution Helpfull? Yes (3) | No   

sumit jain  (9 years ago)

No. ÷ 13 remainder = 11
No. ÷ 17 remainder = 9
No. = 13a + 11 = 17b + 9

13a + 11 = 17b + 9
13a = 17b – 2
13a = 13b + (4b – 2)
a = 13b/13 + (4b – 2)/13
= b + (4b – 2)/13
(4b – 2) is dividable by 13

trying values of b = 1, 2, 3, ...
least value of b
if b = 7
a = 7 + 2 = 9

least No.
No. = 13a + 11
= 117 +11 = 128
not in the option

as number (4b – 2) is divisible by 13 next value of b = 7 + 13 = 20

next value b =20
a = b + (4b – 2)/13
= 20 + 6 = 26
No. = 13a + 11
= 338 +11 = 349
in the option ------- c
-------

Is this solution Helpfull? Yes (1) | No (2)  

Anil Kumar Bharti  (11 years ago)

Ans:24
Exp:
3+5=8 tot
c pay = 8*8=64
then A get=64*3/8=24

Is this solution Helpfull? Yes | No (9)  

uthra murugesan  (8 years ago)

http://www.indiabix.com/aptitude/numbers/001007

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Mohammed Khawaja  (7 years ago)

349 as 349/13 = 26 + remainder of 11 and 349/17 = 20 + remainder of 9

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Archit Jain  (6 years ago)

b 349
(349-11)/13=0 as rem

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