Latest Infosys Aptitude Question SOLUTION: in a pasture, the grass grows at an even rate. 40 cows can completely eat the grass in 40 days, if there are 30 cows the grass last fot 60 days, for how long it is sufficient for 2

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in a pasture, the grass grows at an even rate. 40 cows can completely eat the grass in 40 days, if there are 30 cows the grass last fot 60 days, for how long it is sufficient for 20 cows
1) 80 2)90 3)100 4)120 5 )none

Asked In Infosys (12 years ago)

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srikanth yeluri  (8 years ago)

Ans: 80Reason:The days will be increased by 20 as the number of cows decreases by 10

Is this solution Helpfull? Yes (2) | No   

ooh  (7 years ago)

Let I be the initial Grass
g br the rate of growth of grass per day
r be the rate of consumption of grass by one cow in one day

For 40 cows
I+40g=40*40r -------------------------1
for 30 cows
I+60g=30*60r --------------------------2
Then for 20 cows
I+ng=20*n*r -------------------------3
where n is the no of days

Subtracting the first two equation and dividing it by 20
g=10r
Subtracting the equations 2 and 3 and subustituting the value of g

we get
n=120

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Md Afsar Ali  (10 years ago)

ans-120days

Is this solution Helpfull? Yes (1) | No (4)  

mayank madhukar  (7 years ago)

40 cow can completely eat the grass in 40 days it means there is 40 * 40 = 1600 cow are able to eat the food

for 20 cows the solution is like this-
20*x=1600
(where x is the no of days)
x=80

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shipra  (8 years ago)

80 no of days inc by 20 as cow dec by 10

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