Latest exam Aptitude Question SOLUTION: Find the center, foci, vertices, and co-vertices {{{ (x+1)^2/4 + y^2/1 =1 }}} And {{{ 16(x+1)^2 + 9(y-1)^2 =144 }}}

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(#M40047456) EXAM Numerical Ability question Keep an EYE

Find the center, foci, vertices, and co-vertices

{{{ (x+1)^2/4 + y^2/1 =1 }}}

And {{{ 16(x+1)^2 + 9(y-1)^2 =144 }}}

Asked In exam (10 years ago)

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