Latest exam Aptitude Question SOLUTION: 8-(2x3-9)= Please take me step by step on how to solve this. 2 to the 4th power plus 2 cubed - 10 divided by (-1) to the 4th power=

Follow Quotesrain

exam Question Papers:

exam Select Another Category Numerical Ability Select Another Topic

Maths Puzzle

exam Question Topics

Category (66)

General Ability (20)

General Knowledge(6)

HR Interview (5)

Interview(3)

Logical Reasoning (56)

Numerical Ability (85560)

Programming (1)

Verbal Ability (5)

Advertisements

Previous Question: Over what interval of the domain is this function decreasing: f(x) = x + 4? @ This linear function is always increasing; m > 0. Identify intervals on which a function increases, d Next Question: 6(2y+1) 2(5y-7) -------- - --------- y^2-100 y^2-100

(#M40047518) EXAM Numerical Ability question Keep an EYE

8-(2x3-9)=
Please take me step by step on how to solve this.

2 to the 4th power plus 2 cubed - 10 divided by (-1) to the 4th power=: Asked In exam (10 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

Advertisements

Read Solution (0) :

Please Login to Read Solution.

Previous Question: Over what interval of the domain is this function decreasing: f(x) = x + 4? @ This linear function is always increasing; m > 0. Identify intervals on which a function increases, d Next Question: 6(2y+1) 2(5y-7) -------- - --------- y^2-100 y^2-100

Login
Register

Sponsored Links

Advertisements

Challenger of the Day

no image

Dimple

India

Punjab

Time: 00:01:33

Points

19

Maths Quotes

A man whose mind has gone astray should study mathematics.

Francis Bacon

THROUGH SCIENCE WE DEVELOPED, AND MATHEMATICS IS THE MOTHER OF THE SCIENCE.

Lukman Hussaini

Placed User Comments

M4Math helped me a lot.

Vipul Chavan 4 years ago

Thanks m4 maths for helping to get placed in several companies.
I must recommend this website for placement preparations.

yash mittal 4 years ago

2524K+Registerd user
1767K+Engineers
757K+MBA Asprirant
3K+Enginnering College
250+Company Exam
150K+Interview Questions

All rights are reserved to @m4maths.com