Latest exam Aptitude Question SOLUTION: THE PEROD OF A SIMPLE PENDULUM IS DIRECTLY PROPORTIONAL TO THE SQUARE ROOT OF ITS LENGTH. IF A PENDULUM HAS A LENGTH OF 6 FEET AND A PERIOD OF 2 SECONDS, TO WHAT LENGTH SHOULD IT

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Previous Question: 3 radical 4*x to the 3rd y to the 5th *3 radical 12y Next Question: can someone check this for me PLEASE? X^2 OVER X-3 MINUS 9 OVER X-3 X^2-9 OVER X-3 EQUAL 9 OVER X-3

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THE PEROD OF A SIMPLE PENDULUM IS DIRECTLY PROPORTIONAL TO THE SQUARE ROOT OF ITS LENGTH. IF A PENDULUM HAS A LENGTH OF 6 FEET AND A PERIOD OF 2 SECONDS, TO WHAT LENGTH SHOULD IT BE SHORTENED TO ACHIEVE A 1 SECOND PERIOD?: Asked In exam (10 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: 3 radical 4*x to the 3rd y to the 5th *3 radical 12y Next Question: can someone check this for me PLEASE? X^2 OVER X-3 MINUS 9 OVER X-3 X^2-9 OVER X-3 EQUAL 9 OVER X-3

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