Latest Infosys Aptitude Question SOLUTION: The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is: 1)-4.37% 2)-5% 3)-6% 4)-8.75%

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The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
1)-4.37%
2)-5%
3)-6%
4)-8.75%

Asked In Infosys (12 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

Shiv Kumar  (12 years ago)

5%

Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
Increase% = ( 87500 / 175000) x 100 % = 50%.
average = 50/10 % = 5%.

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Susmita Das  (8 years ago)

Approx 5%
Increase in 10years is 87500.
Increase per year is (87500)/10 = 8750
Percentage increase = (8750/17500)*100 = 5%

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Vignesh  (12 years ago)

8.75%
Decade = 10years
In 10 years, population inreased from 1,75,000 to 2,62500
(i.eI inreased in 10years = 2,62,500 - 1,75,000
=87500
Therefore for 1 years, increase population = 87500/10
=8750
So, increasing percentage = 8.75%

Is this solution Helpfull? Yes (2) | No (23)  

tumati koushik  (6 years ago)

4.37%

Increase in 10 years = (262500 - 175000) = 87500.
Therefore for 1 years, increase population = 87500/10
=8750

first year increase percentage=(8750/175000) x100=5%
second year population =175000+8750=183750
second year increase percentage=(8750/183750)x100=4.76%

similarly for
third year 4.54%
fourth year 4.34%
fifth year 4.16%
sixth year 4%
seventh year 3.84%
eighth year 3.7%
ninth year 3.57%
tenth year 3.44%

average we get 4.37%

Is this solution Helpfull? Yes (2) | No (3)  

anchal gupta  (6 years ago)

2 is the answer i.e 5% because in 10 years the increase would be 50% so yearly increase would be 5%

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