Latest exam Aptitude Question SOLUTION: Tina can run 12 mi in the same time it takes her to bicycle 72 mi. If her bicycling rate is 20 mi/h faster than her running rate, find each rate.

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Previous Question: (-6a3b4)2 (x + 9)(x - 9) (3x - 7)2 (3x + 6)(4x - 7) please simplify these above problems thanks bunches Next Question: I am not sure if I am doing this right. Solve for K. a/b=b/a+1/k (bak) a/b=(bak)b/a+1/k(bak) a^2k=b^2k+ba a^2k-b^2k=ba k(a^2-b^2)=ab k=ab/a^2-b^2

(#M40069101) EXAM Numerical Ability question Keep an EYE

Tina can run 12 mi in the same time it takes her to bicycle
72 mi. If her bicycling rate is 20 mi/h faster than her running rate, find each
rate.: Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: (-6a3b4)2 (x + 9)(x - 9) (3x - 7)2 (3x + 6)(4x - 7) please simplify these above problems thanks bunches Next Question: I am not sure if I am doing this right. Solve for K. a/b=b/a+1/k (bak) a/b=(bak)b/a+1/k(bak) a^2k=b^2k+ba a^2k-b^2k=ba k(a^2-b^2)=ab k=ab/a^2-b^2

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