Latest Syntel Aptitude Question SOLUTION: Walking 6/7th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is: 1. 2 hour 2. 1 hr 12 min. 3. 1 hr 15 min. 4. 45 min

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(#M40006927) SYNTEL Numerical Ability question Basic numeracy problem Keep an EYE

Walking 6/7th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is:
1. 2 hour
2. 1 hr 12 min.
3. 1 hr 15 min.
4. 45 min

Asked In Syntel (12 years ago)

Solved aruna Read Solution (6)

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Read Solution (6) :

aruna  (12 years ago)

option 2 1 hour 12 minutes

As the distance is same
s*t=6/7s*(t+12)
t=72 min
1 hour 12 min

Is this solution Helpfull? Yes (22) | No (8)  

duggineni sushma  (9 years ago)

6/7 of s
so 7/6 of time we get.
then new time=7/6 t
usual time =t
then 7/6-t=12/60
(1/6)t=1/5
t=6/5hours
i.e 6/5*60=72 mins=1 hour 12 mins

Is this solution Helpfull? Yes (10) | No   

aayush  (10 years ago)

t is inversely prpotional to speed
t=7/6 1/6 bigger so
1/6*x=12
x=1hr 12 min

Is this solution Helpfull? Yes (4) | No   

Pratyush  (9 years ago)

Justification:
New speed = (6/7) of usual speed.
New time = (7/6) of usual time.
Therefore (7/6 of usual time)- (usual time) = (1/5) hr.
=> (1/6 of usual time)= (1/5) hr
=> usual time = (6/5) hr
= 1 hr 12 min.

Is this solution Helpfull? Yes (2) | No (1)  

Suyash  (7 years ago)

Distance traveled is same in both the case . Let distance be D.
Now, let usual speed is x . so , 6/7 of usual speed is (6/7)x.

Now, it is given that when men walks 6/7th of his usual speed, he is 12 minutes too late . Which means difference between usual time taken to the time taken when he is walking (6/7) of his usual speed is 12.

We know that -
Distance/Speed=Time
Therefore,
(D/(6x/7))-(D/x)=12
Solving this we get-
D/x=72min. which is nothing but usual speed.
Now converting it into hour we get our answer which is 1hr 12min.

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ANIL KUMAR  (7 years ago)

1hr 12 min

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