Latest Syntel Aptitude Question SOLUTION: A bus started from bustand at 8.00am, and after 30 minutes staying at destination, it returned back to the busstand. The destination is 27 miles from the busstand. The speed of the

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(#M40006986) SYNTEL Numerical Ability question Miscellaneous problem Keep an EYE

A bus started from bustand at 8.00am, and after 30 minutes staying at destination, it returned back to the busstand. The destination is 27 miles from the busstand. The speed of the bus is 18mph. In return journey bus travels with 50% fast speed. At what time it returns to the busstand?

Asked In Syntel (12 years ago)

Solved Anandeeswari Read Solution (4)

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Read Solution (4) :

Anandeeswari  (10 years ago)

A---------->B
A->B
time= 27/18=3/2hour= 90 min
A reaches B at 9.30
and waits in B for 30min
b returns travelat 10 am
speed=(150/100)18=27mph
return time= 27/27=1hour
B reaches A at 11am

Answer: 11am

Is this solution Helpfull? Yes (38) | No   

mounika  (10 years ago)

bus reaches at10:45

Is this solution Helpfull? Yes (2) | No (13)  

Devendra  (9 years ago)

bus stand to destination will be covered in 1.5 hour so it will reach at destination 9:30 am after that 30 min rest . Then at 10:00 am it will start journey again.As in question specified returning speed will be 50% fast so new speed will be 18 of 150% that is 27mph so it will cover the distance from destination to bus stand in 1 hour.
At 11:00 it will be in the bus stand.

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venkata pruthvi moyila  (10 years ago)

Bus Reaches at 1:00 P.M

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