Latest Syntel Aptitude Question SOLUTION: Two pipes A and B can fill a tank in 72 hours, B and C can fill it in 120 hours and pipes A and C can fill it in 90 hours. Then the pipe A alone can fill it in? [A] 150 h [C] 80 h

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(#M40007048) SYNTEL Numerical Ability question pipes and cisterns problem Keep an EYE

Two pipes A and B can fill a tank in 72 hours, B and C can fill it in 120 hours and pipes A and C can fill it in 90 hours. Then the pipe A alone can fill it in?
[A] 150 h
[C] 80 h
[B] 120 h
[D] 90 h

Asked In Syntel (12 years ago)

Solved Abha Read Solution (5)

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Read Solution (5) :

shivang  (10 years ago)

2a+2b+2c=1/72+1/120+1/90
a+b+c=1/60
a=1/60-1/120=1/120
=120 hr ans

Is this solution Helpfull? Yes (20) | No   

Abha  (11 years ago)

(A+B)'s 1 hr work=1/72 So A's 1 hr work=1/72-B
(B+C)'s 1 hr work=1/120 so C's 1 hr work=1/120-B
given (A+C)'s 1 hr work=1/90
so (1/72-B)+(1/120-B)=1/90
=> 8/360-2B=1/90
=> 8/360-1/90=2B
=> 4/360=2B so B's 1 hr work=1/180
now A+B 1 hr work =1/72
so A 1 hr work=1/72-1/180
=3/360
=1/120
so A can fill d tank in 120 hrs

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sompon temtheerakij  (9 years ago)

rate of 2(A+B+C) = 1/72+1/120+1/90
rate of A+B+C = 1/144+1/240+1/180
rate of A = 1/144+1/240+1/180-1/120 = 1/120 cis./hrs. = 120 hrs./cis.

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Saran  (9 years ago)

A+B=72
B+C=120
A+C=90 LCM=360
perday work a+b=5,b+c=3,a+c=4
A+B+B+C+A+C=2(A+B+C)
2(A+B+C)=12
A+B+C=6
(a+b+c)-(b+c)=a+b+c-b-c=6-3
a=3 so,totalwork=360
360/3=120 ANS=120 h

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Panswari Hembram  (10 years ago)

ans-60
a+b=1/72
b+c=1/120
c+a=1/90
2(a+b+c)=1/30
a+b+c=1/60

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