Latest CTS Aptitude Question SOLUTION: There are coins of Rs.5, 2,1,50p,25p,10p,5p. Each one has got a weight. Rs 5 coin weighs 20gms.find the minimum number of coins to get a total of 196.5gms.

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(#M40007122) CTS Numerical Ability question Coins problem Keep an EYE

There are coins of Rs.5, 2,1,50p,25p,10p,5p. Each one has got a weight. Rs 5 coin weighs 20gms.find the minimum number of coins to get a total of 196.5gms.

Asked In CTS (12 years ago)

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Read Solution (4) :

Promila Dahiya  (11 years ago)

Explanation:
Rs. 5 taken 9 coins = 9 x 20 = 180 gms
Rs. 2 taken 2 coins = 2 x 8 = 16 gms
10paise taken 1 coin= 1 x 0.5= .5 gms

Is this solution Helpfull? Yes (15) | No (39)  

Manish  (8 years ago)

Rs 5 coin = 20 gm (5*4)
RS 2 coin= 8 gm(2*4)
similarly Rs 1 coin = 4gm, 50paise= 2gm, 25 paise= 1gm, 10 paise= 0.4gm, 5paise =0.2 gm
So we could get 196 gm by taking 9 coins of rs 5 and 2 coins of rs 2. However we could never obtain that additional 0.5 gm . (Odd could not be obtained by adding evens). Hence we could never obtain the mentioned weight :P

Is this solution Helpfull? Yes (5) | No (2)  

niranjan  (8 years ago)

Ans: 60

Is this solution Helpfull? Yes (1) | No (5)  

Bhagyesh Joshi  (7 years ago)

Rs 5 coin = 20 gm (5*4)
RS 2 coin= 8 gm(2*4)
Similarly
Rs 1 coin = 4gm
50paise= 2gm 25 paise= 1gm
10 paise= 0.4gm
5paise =0.2 gm

We want weight of 196.5

5Rs 9 Coins = 9*20 (No of Coins * Weight) =180 gm
2Rs 2 Coins = 2*8 (No of Coins * Weight) =196 gm
5Paisa 2 Coins = 2*0.25 (No of Coins * Weight) =196.5 gm

Is this solution Helpfull? Yes | No (1)  

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